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rusak2 [61]
2 years ago
8

when preparing to pump down a refrigeration system for the purpose of removing an expansion valve, it would make the most sense

for a technician to close .
Engineering
1 answer:
tino4ka555 [31]2 years ago
8 0

When preparing to pump down a refrigeration system for the purpose of removing an expansion valve, it would make the most sense for a technician to close the service valve.

<h3>What is a Refrigeration system?</h3>

This is used in various sectors and department and they perform functions such as cooling or maintaining room temperature at a set value. This system removes heat away from the area it wants to cool through different techniques and is composed of four major parts which are:

  • Compressor
  • Condenser
  • Expansion device
  • Evaporator

The service valve allows the refrigeration gauges to be attached to the system so as to ensure that they are well coupled. This therefore means that it has to be closed before the expansion valve or other parts can be removed and makes it the most appropriate thing for the technician to do in this type of scenario.

Read more about Refrigeration system here brainly.com/question/12135611

#SPJ1

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Answer You ask your coach
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4 years ago
The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affec
LenaWriter [7]

Answer: Increase in the population of lower organisms.

Explanation: Raccoons are mesopredators found in the middle levels of food webs and have critical impacts on the dynamics of many other species. Thus, they greatly contribute to the functioning of the ecosystem.

They are naturally equipped to checkmate the population size of other organism that are below them (i.e., their preys) in the food web. They are; predators, pathogen carriers (such as rabies), and competitors, as they compete with some specialist in the food web.

Hence, the decrease in the population of raccoons will lead to the increase in the population size of lower organisms they prey on in the food web or chain.

3 0
3 years ago
Heat is transferred at a rate of 2 kW from a hot reservoir at 875 K to a cold reservoir at 300 K. Calculate the rate at which th
blsea [12.9K]

Answer:

The correct answer is 0.004382 kW/K, the second law is a=satisfied and established because it is a positive value.

Explanation:

Solution

From the question given we recall that,

The transferred heat rate is = 2kW

A reservoir cold at = 300K

The next step is to find the rate  at which the entropy of the two reservoirs changes is kW/K

Given that:

Δs =  Q/T This is the entropy formula,

Thus

Δs₁ = 2/ 300 = 0.006667 kW/K

Δs₂ = 2 / 875 =0.002285

Therefore,

Δs = 0.006667 - 0.002285

= 0.004382 kW/K

Yes, the second law is satisfied, because it is seen as positive.

8 0
4 years ago
A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed
attashe74 [19]

Answer:

W=-123.8Btu

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

Q-W=\Delta U

Thus, we must now compute \Delta U in terms of Cv as follows:

\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu

Now, since heat is given off, its sign is negative, thus, the work is computed as:

W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

8 0
4 years ago
I am making composites of silicone rubber and copper particles; by mixing thermally conductive particles into the thermally insu
Gelneren [198K]

Answer:

The composition of Composite of Volume basis is 2.154% Copper and 97.83% Rubber.

Explanation:

Let us assume that the total mass of composite is 100 lbm So as per the given conditions

  • 15 lbm is copper and 85 lbm is rubber.
  • Density of rubber is 70 lbm/ft3
  • Specific gravity of Copper is 9

So As per the formula of specific gravity

                                         S_{cu}=\frac{\rho_{cu}}{\rho_w}

here density of water is 62.4 lbm/ft3

Solving for Density of Copper gives

                                        S_{cu}=\frac{\rho_{cu}}{\rho_w}\\9=\frac{\rho_{cu}}{62.4}\\\rho_{cu}=9 \times 62.4\\\rho_{cu}=561.5 lbm/ft3

For composition on volume basis, volume of individual components and composite are calculated as

                                          V_{cu}=\frac{m_{cu}}{\rho_{cu}}\\V_{cu}=\frac{15}{561.5}\\V_{cu}=0.0267 ft^3\\\\V_{r}=\frac{m_{r}}{\rho_{r}}\\V_{r}=\frac{85}{70}\\V_{r}=1.214 ft^3\\\\V_{c}=V_{r}+V_{cu}\\V_{c}=1.214+0.0267 \\V_{c}=1.2409 ft^3

The composition is given as

c_{cu}=\frac{V_{cu}}{V_{c}}\\c_{cu}=\frac{0.0267}{1.2409} \times 100 \%\\c_{cu}=2.154 \%\\\\c_{r}=\frac{V_{r}}{V_{c}}\\c_{r}=\frac{1.214}{1.2409} \times 100 \%\\c_{r}=97.83 \%

So the composition of Composite of Volume basis is 2.154% Copper and 97.83% Rubber.

6 0
3 years ago
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