Question

Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part.Ex: If the input is 130 50 130, the output is: 80 0 80. Thus, find the smallest value, and then subtract it from all three values, thus removing the gray.

Answer 1

Answer:

Using C++, the program appears as follows

#include <iostream>

using namespace std;

int main() {

int r,g,b,small;

//input values

cin>>r>>g>>b;

//find the smallest value

if(r<g && r<b)

small=r;

else if(g<b)

small=g;

else

small=b;

//subtract smallest of the three values from rgb values hence removing gray

r=r-small;

g=g-small;

b=b-small;

cout<<r<<" "<<g<<" "<<b<<endl;

}

Answer 2

Answer:

Using C++, the program is as follows;

#include <iostream>

using namespace std;

int main() {

int r,g,b,small;

//input values

cin>>r>>g>>b;

//find the smallest value

if(r<g && r<b)

small=r;

else if(g<b)

small=g;

else

small=b;

//subtract smallest of the three values from rgb values hence removing gray

r=r-small;

g=g-small;

b=b-small;

cout<<r<<" "<<g<<" "<<b<<endl;

}