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Sliva [168]
3 years ago
9

Stephen had 24 miniature cars

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0
Um.... I am confused I do not know what u are asking me.




I am so sorry that I can not help , but isf I knew it I would help.
You might be interested in
Mr. Rifkin had 240 digital and manual cameras. After donating 82 digital cameras and 26 manual cameras, he had three times as ma
puteri [66]
After the donation,
3m + m = 132
manual = 33
digital = 99

Before the donation, he had 82 more digital and 26 more manual cameras.
82 + 99 = 181 digital
26 + 33 = 59 manual
For a double check, before donation,
digital + manual = 240
181 + 59 = 240
So, to begin with, the number of digital cameras = 181.


3 0
4 years ago
Read 2 more answers
20 - (3 2/3 + 2 1/4 + 2 1/3) = ?
Alex777 [14]

Answer:

20-5 11/12= 9 11/12

Step-by-step explanation:

we do (3 2/3 + 2 1/4+ 2 1/3 )which is

           3 8/12.    2 3/12    2 4/12 (common denominator)

then add 3 8/12 and 2 3/12 and 2 1/3 to get 10 1/12 then we get 20- 10 1/12 to get a final answer of 9 11/12

5 0
3 years ago
17. What is the area of the figure below?
Sidana [21]

If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 cm^{2}.

Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.

Area of figure=Area of rectangle+Area of square+Area of triangle

Area of rectangle=length*breadth

Area of square=Side*Side

Area of triangle=1/2 *Base*Height

Area of figure=8*4+3*3+1/2 *3*5

=32+9+1/2 *15

=41+15/2

=(82+15)/2

=97/2

=48.5 cm^{2}

Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 cm^{2}.

Learn more about area at brainly.com/question/25292087

#SPJ9

7 0
2 years ago
Find the value of x. Give reasons to justify your solution. C ∈ AE
saw5 [17]

Answer:

x = 11º

Step-by-step explanation:

1. Notice Parallel Lines

2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)

3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º

4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.

5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).

  • 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
  • 3x = 33 (inverse operations; divide by 3)
  • x = 11º (remember to apply units)
7 0
3 years ago
5x+3 (x-2)=90<br>please tell me the answer
Yuliya22 [10]
5x+3(x-2)=90
5x+3x-6=90
8x-6=90
+6 +6
8x=96
\8 \8
X=12
3 0
3 years ago
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