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3 years ago

11

What is the greatsest common factor of

24 {a}^{3} c" alt="24 {a}^{3} c" align="absmiddle" class="latex-formula">
and 3a

1 answer:

coldgirl [10]3 years ago

4 0

Think it is just 3a

3a x 6 =24a

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−3 1/3÷1.2= write it as a mixed number i simplest form

GenaCL600 [577]

Answer:

I got -2.7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve for r. Show your work!<br> 12 =R– (34 – 2)<br><br> Helpppp!!

amm1812

Answer:

r = 44

Step-by-step explanation:

12 = r - (34 - 2)

Solve for r

___________

To solve, we need to isolate r.

Distribute the negative sign with the numbers within the parenthesis :

12 = r - 34 + 2

Add like terms :

12 = r - 32

Add 32 to both sides :

44 = r

r = 44

4 0

3 years ago

Read 2 more answers

In the parallelogram shown in the picture solve for Z

deff fn [24]

In a parallelogram, opposite angles are congruent.

Since angles z and 124° are opposite angles in the parallelogram, they are congruent angles.

Therefore we have:

$z=124°$

5 0

11 months ago

How to solve <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B4%7D%20x%20%7B%7D%5E%7B2%7D%20%20%3D%20x%20%2B%202" id="TexFormu

Vikentia [17]

Answer:

➩ $x=2,-\frac{2}{3}$

Step-by-step explanation:

$\sqrt{4x^2}=x+2$

➨ We can also solve by completing both squares, however. Since we can pull out the square root.

$\sqrt{4x^2}=|2x|$ ➩ Define of Absolute Value/Square Root

➩ $\sqrt{x^2}=|x|$

Thus, our new equation is ➩ $|2x|=x+2$

To solve an absolute-value equation, let there be two conditions.

➨ Where x ≥ 0

$2x=x+2\\$

Move x to another side

$2x-x=2\\x=2$

➨ Where x < 0

$-2x=x+2\\-2x-x=2\\-3x=2\\x=\frac{2}{-3}\\x=-\frac{2}{3}$

3 0

3 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago