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Rama09 [41]
2 years ago
11

A spring has a spring constant k = 8.75 n/m. if the spring is displaced 0.150 m from its equalibirum position. What is the force

that the spring exerts?
Physics
1 answer:
lisabon 2012 [21]2 years ago
8 0

The force that the spring exerts is = 1.31 N

<h3>How can we calculate the force that the spring exerts?</h3>

The spring force in the spring depends on the spring's displacement and the force constant of the particular spring. The below expressions show the force that the spring exerts,

F=kx

Here, we are given,

k= The spring constant of a spring = 8.75 N/m.

x= The displacement of the string is = 0.150 m

Now, we replace the known values in the above equation, we can find :

F=kx

Or, F= 8.75 \times 0.150

Or, F= 1.3125 N

Or, F≈ 1.31 N

Now, from the above calculation we can conclude that the force that the spring exerts is 1.31 N.

Learn more about the Spring constant:

brainly.com/question/12253978

#SPJ4

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A bicycle has wheels of 0.70 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 10.8 s. Wh
Anna11 [10]

Answer:

\alpha=0.16\frac{rad}{s^2}

Explanation:

Angular acceleration is defined as the variation of angular speed with respect to time:

\alpha=\frac{\omega}{t}

The relation between the angular speed and the linear speed is given by:

\omega=\frac{v}{r}

Replacing (2) in (1):

\alpha=\frac{v}{rt}

We need to convert \frac{km}{h} to \frac{m}{s}:

22\frac{km}{h}*\frac{1h}{3600s}*\frac{1000m}{1km}=6.11\frac{m}{s}

Recall that:

r=\frac{d}{2}=\frac{0.7m}{2}=3.5m

Replacing:

\alpha=\frac{6.11\frac{m}{s}}{(3,5m)(10.8s)}\\\alpha=0.16\frac{rad}{s^2}

3 0
4 years ago
uppose one gallon of gasoline produces 1.17×108 J of energy, and this energy is sufficient to operate a car for 18.3 miles. An a
EleoNora [17]

Answer:

4.5 x 10^6 miles

Calculations can be viewed on the snapshot attached to this reply.

Thanks

8 0
4 years ago
Compare convergent plate boundaries that have the same density to convergent plate boundaries with different densities.
andrey2020 [161]

Answer:

If the two plates are of equal density, they usually push up against each other, forming a mountain chain. If they are of unequal density, one plate usually sinks beneath the other in a subduction zone. Hope this helps!

Explanation:

4 0
4 years ago
A 0.83-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one
vodomira [7]

Answer:

1.66 kg

Explanation:

Given that a 0.83-kg block is hung from and stretches a spring that is attached to the ceiling.

From Hook's law

F = Ke

But F = mg

Substitute mg for force in the Hook's law

Mg = ke

0.83 × 9.8 = ke

Make K the subject of formula

8.134 = Ke

K = 8.134 /e

Given that a second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples.

That is

(0.83 + M) × 9.8 = K (3e)

Substitutes K into the above equation

(0.83 + M) × 9.8 = 8.134 / e (3e)

The e will cancel out

(0.83 + M) × 9.8 = 24.402

0.83 + M = 24.402/9.8

0.83 + M = 2.49

M = 2.49 - 0.83

M = 1.66 kg

Therefore, the mass of the second block is 1.66kg

6 0
3 years ago
A resistor, inductor, and capacitor are connected in series, each with effective (rms) voltage of 65 V, 140 V, and 80 V respecti
Morgarella [4.7K]

Answer:

The value of the effective (rms) voltage of the applied source in the circuit is 132 V

Explanation:

Given;

effective (rms) voltage of the resistor, V_R = 65 V

effective (rms) voltage of the inductor, V_L = 140 V

effective (rms) voltage of the capacitor, V_C = 80 V

Determine the value of the effective (rms) voltage of the applied source in the circuit;

V= \sqrt{V_R^2 + (V_L^2-V_C^2} )\\\\V= \sqrt{65^2 + (140^2-80^2} )\\\\V = \sqrt{4225+ 13200} \\\\V = \sqrt{17425} \\\\V = 132 \ V

Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.

6 0
4 years ago
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