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Rama09 [41]
2 years ago
11

A spring has a spring constant k = 8.75 n/m. if the spring is displaced 0.150 m from its equalibirum position. What is the force

that the spring exerts?
Physics
1 answer:
lisabon 2012 [21]2 years ago
8 0

The force that the spring exerts is = 1.31 N

<h3>How can we calculate the force that the spring exerts?</h3>

The spring force in the spring depends on the spring's displacement and the force constant of the particular spring. The below expressions show the force that the spring exerts,

F=kx

Here, we are given,

k= The spring constant of a spring = 8.75 N/m.

x= The displacement of the string is = 0.150 m

Now, we replace the known values in the above equation, we can find :

F=kx

Or, F= 8.75 \times 0.150

Or, F= 1.3125 N

Or, F≈ 1.31 N

Now, from the above calculation we can conclude that the force that the spring exerts is 1.31 N.

Learn more about the Spring constant:

brainly.com/question/12253978

#SPJ4

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