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2 years ago

How do I answer number 5?

Physics

1 answer:

Julli [10]2 years ago

7 0

Answer:

He needs to throw the trash before he gets to the Trash can because he

needs some force for it to be able to go in because it he throw it after he passed it, it would not make it because your going a certain speed, and if you try to throw it when it is right in front of you, it will still miss because it is still going the same speed as the car.

Explanation:

Hope that helps you :)

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How to find coefficient of lift from coefficient of pressure?

Alona [7]

It is the number in front of the equation

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3 years ago

A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1

lisabon 2012 [21]

Answer:

$\alpha =10.93radian/sec^2$

Explanation:

We have given given the final angular velocity $\omega _{final}=13.5rad/sec$

And $\omega _{initial}=22rad/sec$

Displacement $\Theta =13.8radian$

We have to find the angular acceleration $\alpha$

According to law of motion $\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta$

So $13.5^2=22^2+2\times \alpha \times 13.8$

$\alpha =-10.93radian/sec^2$

In question we have tell about magnitude only so $\alpha =10.93radian/sec^2$

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3 years ago

O SIGNIFICADO ESPECÍFICO NA FÍSICA DO TERMO “FORÇA”? E CITE 03(TRÊS) EXEMPLOS;

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Answer:

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2 years ago

What property appplies to the element radon?

Arlecino [84]

Radioactive element
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2 years ago

A scared elephant has a mass of 7000 kg. The mouse that frightened the elephant is 0.02 kg. The distance between the elephant an

arsen [322]

a. $9.34\cdot 10^{-9} N$

The gravitational force between two objects is given by:

$F=G\frac{Mm}{r^2}$

where

G is the gravitational constant

M,m are the masses of the two objects

r is the separation between the objects

In this problem, we have:

M = 7000 kg is the mass of the elephant

m = 0.02 kg is the mass of the mouse

r = 1 m is the separation

Substituting into the equation, we find the gravitational force exerted by the elephant on the mouse:

$F=(6.67\cdot 10^{-11}) \frac{(7000)(0.02)}{1^2}=9.34\cdot 10^{-9} N$

b. $-9.34\cdot 10^{-9}N$

We can solve this part by keeping in mind Newton's third law of motion, which states that:

"When an object A exerts a force (action) on object B, then object B exerts and equal and opposite force (reaction) on object A".

In our problem, we can identify the elephant as object A and the mouse as object B: this means that the gravitational force exerted by the elephant on the mouse is the action, while the gravitational force exerted by the mouse on the elephant is the reaction. The two forces are equal in magnitude and opposite in direction: therefore, the gravitational force exerted by the mouse on the elephant is equal to

$F=-9.34\cdot 10^{-9}N$

where the negative sign simply means that the direction is opposite.

6 0

3 years ago