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Dafna11 [192]
1 year ago
6

A police officer uses a radar gun to determine the speed of a car. A specialized radar gun uses ultraviolet light to determine t

he speed.
Physics
1 answer:
soldi70 [24.7K]1 year ago
4 0

Option (A) and option (D) are the correct answers.

Transverse waves and electromagnetic waves correctly describe the wave used by police , i.e. ultraviolet light.

<h3>What are transverse waves?</h3>

A transverse wave is an oscillating wave in physics that <u>advances in the opposite direction of its </u><u>oscillations</u>. A longitudinal wave, on the other hand, moves in the direction of its oscillations. Transverse waves <u>include </u><u>water</u><u> </u><u>waves</u>.

<h3>What are electromagnetic waves?</h3>

In terms of science, electromagnetic radiation is made up of electromagnetic field waves that are traveling through space while carrying radiant electromagnetic energy. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves. These waves are all a component of the electromagnetic spectrum.

To learn more about electromagnetic radiation:

brainly.com/question/10759891

#SPJ4

I understand that the question you are looing for is "A police officer uses a radar gun to determine the speed of a car. A specialized radar gun uses ultraviolet light to determine the speed.

What describes the wave used? check all that apply.

A. transverse

B. longitudinal

C. heat

D. electromagnetic

E. sound "

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The Burj Khalifa in Dubai is the world's tallest building. The structure is 828 m 828 m (2716.5 ft) and has more than 160 storie
Natasha_Volkova [10]

Answer:

h = height of the hotel room from the ground floor = 237.4m

Explanation:

Change in Potential Energy of tourist = ΔPE = PE2 – PE1 = mgh

PE1 is the potential energy of tourist at the ground floor

PE1 is the potential energy of tourist at the top (hotel room)

Given

PE1 = − 2.01 × 10⁵ J

PE2 = 0J

PE2 – PE1 = mgh

0 – (− 2.01 × 10⁵ J) = mgh

2.01 × 10⁵ J = 86.4×9.8×h

h = 2.01 × 10⁵/(86.4×9.8) = 237.4m

8 0
3 years ago
Based on their colors, which of the following stars is hottest? Which is coolest? Archenar (blue), Betelgeuse (red), Capella (ye
Cloud [144]

Answer: The hottest star is Archenar( blue) and the coolest star is Betelgeuse

Explanation:

Objects emit radiation that depends exclusively on their temperature. At an ambient temperature, the radiation emitted by an object is in the infrared spectrum (we could only see it with a special camera). If we heat it we will see that it first turns red (whose state we call “red hot”) because it is the lowest and least energetic wavelength of all.

If we continue to heat it, the wavelength that it emits to one with more energy will continue to increase and we will see that it turns yellow and then white. This is a signal that is emitting at all frequencies (but mainly in blue).

If we continue to warm a body that is "white hot", it would emit in the ultraviolet spectrum, with what would become ... black! then we would not see it emits light in the visible spectrum (well, we would see a very faint bluish light corresponding to the tail of the distribution of the spectrum it emits, but the peak of that spectrum would be in the ultraviolet).

6 0
3 years ago
Read 2 more answers
On a distance-time graph, time is shown on the y-axis.<br> A) True<br> B) False
Artist 52 [7]

Answer:

false : In distance time graph,time is shown on the x -axis

7 0
2 years ago
Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

1866=4.5\lambda_{B}

\lambda_{B}=414.67 nm

3 0
3 years ago
Sound waves strike a glass and cause it to shatter.
e-lub [12.9K]
1. Resonance. Mechanical waves act on or through a medium, these waves can often have frequencies that are synchronized in a way that makes them act on the matter in the medium more "aggressively."
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