x2=36
We move all terms to the left:
x2-(36)=0
We add all the numbers together, and all the variables
x^2-36=0
a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ‾‾√=144‾‾‾‾√=12
x1=−b−Δ√2a=−(0)−122∗1=−122=−6
x2=−b+Δ√2a=−(0)+122∗1=122=6
Answer:
See answers and explanations below (along with a visual graph)
Step-by-step explanation:
For the function
:
Amplitude: 
Period: 
Phase shift: 
Vertical shift: 
Therefore, for
:
Amplitude:
, which is 2 units above and below the midline (see d)
Period:
, so the cycle will repeat every 3π units
Phase shift:
, or π units to the left
Vertical shift:
, or 1 unit down
False, the estimated square root of 32 is 5.65685424... while 25/2 = 12.5