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2 years ago

Name one similarity and one difference between simple diffusion and facilitated diffusion.

1 answer:

6 0

The movement of particles from an area of high concentration to an area of lower concentration is known as Diffusion. There are two types of Diffusion; simple diffusion and facilitated diffusion.

Simple diffusion and facilitated diffusion have some similarities and differences.

Both simple diffusion and facilitated diffusion are passive processes and do not require energy. They both deliver transport molecules in the direction of a concentration gradient.

There are also some differences. The speed of simple diffusion is low as compared to facilitated diffusion. Simple diffusion does not require the assistance of carrier molecules but facilitated diffusion does.

If you need to learn more about simple diffusion and facilitated diffusion, click here

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!!!!!!!I REALLY NEED HELP PLEASE!!!!!!!!!!!

Brut [27]

Answer:

2:1 Hydrogen:Oxygen for all three answers.

Explanation:

Maltose has 22 hydrogen and 11 oxygen,

glucose and fructose both have 12 hydrogen and 6 oxygen, and water has 2 hydrogen and 1 oxygen.

3 0

3 years ago

s e vapor pressure of the waterretnylene glycol solution at 32 "C? 5. What is the Boiling Point of the solution resulted from th

lyudmila [28]

Answer:

What is the Boiling Point of the solution resulted from the dissolving of 32.5 g of NaCl in 250.0 g of water? 102,31°C

Explanation:

This question involves the Elevation of boiling point

ΔT = Kb . m . i

(T°solution - T°solvent pure) = Ebulloscopic constant . molality . Van 't Hoff factor

Van 't Hoff factor is 2 for NaCl because you have two ions on disociation.

Kb for water is, 0,52 °C . kg/mol - It is a known value.

You know that water pure boils at 100°C so let's build the formula

(T°solution - 100°C) = 0,52 °C.kg/mol . molality . 2

We have to find out the molality (moles of solute/1kg solvent)

In 250 g H2O we have 32,5 g NaCl so the rule of three will be

250 g H2O ______32,5 g NaCl

1000g __________ (1000g . 32,5g) / 250g = 130 g NaCl

Molar mass NaCl : 58,45 g/m

Moles NaCl : mass/ molar mass --> 130g /58,45 g/m = 2,22 m

(T°solution - 100°C) = 0,52 °C.kg/mol . 2,22 mol/gk . 2

T°solution - 100°C = 2,31 °C

T° at boiling point in the solution = 2,31°C + 100°C = 102,31°C

3 0

3 years ago

What is the most important use of an elements atomic number

Setler [38]

Answer:

Atoms of each element contain a characteristic number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another.

8 0

3 years ago

1.A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. How much calcium is contained in 40.0 g of

QveST [7]

These are five questions and five answers.

1) Question 1. A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. How much calcium is contained in 40.0 g of calcium fluoride?

Answer:

20.5 g Ca

Explanation:

Calcium fluoride being a pure substance, has a fixed chemical compositon, which means that their elements (atoms), in any sample, are always in the same proportion.

Then, you can set the followoing proportion:

7.70 g Ca / 15.0 g CaF₂ = x / 40.0 g CaF₂

Now, solve for x:

x = 40.0 g CaF₂ × 7.70 g Ca / 15.0 g CaF₂ = 20.5 g Ca.

The answer must be expressed with 3 significan figures, since the three data are given with 3 significan figures.

2) Question 2. Silver has two isotopes. One isotope contains 60 neutrons and has a percent abundance of 51.839% the other contains 62 neutrons. Give the atomic symbols for the two isotopes.

Answer:

Isotope that contains 60 neutrons: ¹⁰⁷₄₇Ag

Isotope that contains 62 neutrons: ¹⁰⁹₄₇Ag

Explanation:

Isotopes are atoms of the same element, with different number of neutrons, so all the isotopes of an element have the same atomic number, Z (number of protons) and different mass number A (number of neutrons + protons).

The atomic symbols for isotopes uses the chemical symbol of the atom (Ag for silver); a subscript to the left of the chemical symbol that represents the atomic mass (47 for silver); and a superscript to the left of the chemical symbol that represents the mass number.

The mass number, A, for each silver isotope is calculated in this way:

Isotope that contains 60 neutrons: A = 60 + 47 = 107

Isotope that contains 62 neutrons: A = 62 + 47 = 109

Then, the respective atomic symboles are:

Isotope with 60 neutrons: ¹⁰⁷₄₇Ag

Isotope with 62 neutrons: ¹⁰⁹₄₇Ag

3) Question 3. What is the average atomic weight of silver? What is the mass (in grams) of a single chlorine molecule?

Answer:

107.96 amu

Explanation:

The atomic wieght of the elements is the weighted average weight of the different isotopes of the same element found in the nature, taking into account their relative abundance.

Average atomic weight = ∑( abundance × individual atomic weight)

Average atomic weight of silver = (abundace of isotope 1 × atomic weight isotope 1) + (abundance isotope 2 × atomic weight isotope 2)

Abundance isotope 1 = 51.839%

Atomic weight isotope 1 = mass number = 60 neutrons + 47 protons = 107 a.m.u
Abundance isotope 2 = 100% - 51.839% = 48.161%

Atomic weight isotope 2 = 62 neutrons + 47 protons = 109 a.m.u.

Average atomic weight of silve = 107 amu × 51.839% + 109 amu × 48.161% = 107.96 amu

4) Question without number: What is the mass (in grams) of a single chlorine molecule

Answer:

1.177 × 10⁻²² g

Explanation:

The chlorine molecule is diatomic. That means that each molecule contains two atoms. The chemical formula of chlorine molecule is Cl₂.

The mass of one mole of molecules of Cl₂ is 2 × 35.453 g/mol = 70.906 g/mol

Mass of a single molecule = mass of one mol / number of molecules in one mol

Mass of a single molecule = 70.906 g/mol / (6.022 × 10²³ molecules / mol)

Mass of a single molecule = 11.77 × 10⁻²³ g = 1.177 × 10⁻²² g

5) Question 4. How many moles of ethanol (CH₃CH₂OH) are in 141 mg?

Answer:

0.00301 mol

Explanation:

Molar mass of CH₃CH₂OH = 2 × 12.011 g/mol + 6 × 1.008 g/mol + 15.999 g/mol = 46.069 g/mol.

Formula: number of moles = mass in grams / molar mass

Calculation: number of moles = 141 mg × ( 1 g /1000 mg) / (46.069 g/mol = 0.00301 mol

4 0

3 years ago

In a continuous manufacturing process, chlorodifluoromethane (CHClF2), initially at 10 bar and 420 K, passes through an adiabati

salantis [7]

Answer:

GIMME

Explanation:

DEEZ

POINTS

6 0

3 years ago