Question

What is the magnitude of a point charge in coulombs whose electric field 51 cm away has the magnitude 2.5 n/c?

Answer 1

The magnitude of a point charge is 0.189 x 10⁻⁹C.

Steps

We have stated that the point charge's electric field is E=2.5 N/C.

Distance from point charge R = 51 cm = 0.51 m

We are aware that the electric field resulting from a point charge is given as E = 1 / 4π∈₀ × Q / R²

so 2.5 = 9 x 10⁹ Q/ 0.68²

The magnitude of a point charge is 0.189 x 10⁻⁹C.

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.

From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.

learn more about electric field here

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