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3 years ago

What does 34.9cL equal in hL

1 answer:

6 0

Hello,

The answer is "<span>0.00349 hL".

Reason:

34.9cL=0.00349hL

(Remember to go left 6 places when doing this question)

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

</span>

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Electromagnets project student guide <br>y’all i need helppppo

Masja [62]

Answer:

I don't know

Explanation:

you need then search here

7 0

2 years ago

Help!! ASAP plz

VashaNatasha [74]

Can you include an image of the object and it’s dimensions?

4 0

3 years ago

The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five

leva [86]

Answer:

$l = 0.305 \ m$

$f = 3.0*10^{11} \ Hz$

Explanation:

From the question we are told that

The wavelength is $\lambda = 12.2 \ cm = 0.122 \ m$

The number of antinodal planes of the electric field considered is n = 5

The width is mathematically represented as

$l = \frac{ n \lambda}{2}$

$l = \frac{5 * 0.122 }{ 2}$

$l = 0.305 \ m$

Generally the frequency the errors was made is mathematically represented as

$f = \frac{c}{\lamda_k}$

Here c is the speed of light with value $c = 3.0*10^{8} \ m/s$

$\lambda_k$ is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as

$\lambda_k = \frac{ \lambda * \frac{0.04}{2} }{n/2}$

$\lambda_k = \frac{0.122*0.02}{5/2}$

$f = \frac{3.0*10^{8}}{0.000976}$

$f = 3.0*10^{11} \ Hz$

8 0

3 years ago

How can wind change landforms

slamgirl [31]

Well, wind can change landforms by storms, and hurricains, or other things that contain air...
~~~~~~~~~~~~~
Like, over a period of time... Wind can make landforms decrease in size, by weathering.
~~~~~~~~~~~~~~
Hope this helps! :)

5 0

3 years ago

Read 2 more answers

A car with a mass of 500 kg, gets off road and goes straight into a cliff of 30 m with an

mars1129 [50]

Answer:

The velocity of the car when it hits the ground is approximately 55.574 meters per second.

Explanation:

According to this expression, the car goes straight into the cliff and goes down due to gravity, whose situation is described by the Principle of Energy Conservation and supposing that all non-conservative forces are negligible:

$U_{g,1}+K_{1} = U_{g,2}+K_{2}$ (1)

Where:

$U_{g,1}$ , $U_{g,2}$ - Gravitational potential energies of the car at the top and the bottom, measured in joules.

$K_{1}$ , $K_{2}$ - Translational kinetic energies of the car at the top and the bottom, measured in joules.

By definitions of gravitational potential and translational kinetic energies, we expand and simplify the equation above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2} = \frac{1}{2}\cdot m \cdot v_{1}^{2}+m\cdot g \cdot (z_{1}-z_{2})$ (2)

$v_{2}^{2} = v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})$

$v_{2} = \sqrt{v_{1}^{2}+2\cdot g\cdot (z_{1}-z_{2})}$

Where:

$m$ - Mass, measured in kilograms.

$v_{1}$ , $v_{2}$ - Velocity of the car at the top and the bottom, measured in meters per second.

$g$ - Gravitaitional acceleration, measured in meters per square second.

$z_{1}$ , $z_{2}$ - Height of the car at the top and at the bottom, measured in meters.

If we know that $v_{1} = 50\,\frac{m}{s}$ , $g = 9.807\,\frac{m}{s^{2}}$ , $z_{1} = 30\,m$ and $z_{2} = 0\,m$ , then the velocity of the car when it hits the ground is:

$v_{2} = \sqrt{\left(50\,\frac{m}{s} \right)^{2}+2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (30\,m-0\,m)}$

$v_{2}\approx 55.574\,\frac{m}{s}$

The velocity of the car when it hits the ground is approximately 55.574 meters per second.

7 0

3 years ago