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miskamm [114]
2 years ago
7

The period T of a pendulum of length L is measured to determine g at the surface of Earth. The equation used is T=2π√L/g. The ma

ss of the pendulum bob is 10.0 kg, and the length of the pendulum is 1.00 m. Which of the following would contribute most to the expected error in the result?
a. 10% uncertainty in the measurement of the mass.
b. Approximating the value of t as 3.14.
c. Variation in the value of g as the pendulum bob moves along its arc.
d. Using the average period of 10 timed oscillations instead of the period of 1 timed oscillation.
d. Starting the pendulum swinging by releasing it from a horizontal position D. E.
Physics
1 answer:
saul85 [17]2 years ago
4 0

Answer:

C: Variation in the value of g as the pendulum bob moves along its arc.

Explanation:

The formula for period of a simple pendulum is given by;

T = 2π√(L/g)

Where;

L is length

g is acceleration due to gravity

Now, from this period equation, it is clear that the only thing that can affect the period of a simple pendulum are changes to its length and acceleration due to gravity.

Looking at the options, the only one that talks about either the length or gravity as being potential causes of the error is option C

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I would say its a deep ocean trench

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Once potential energy is lost on a roller coaster it cannot be gained all the way back true or false
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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
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Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

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The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

<h3>What is volume?</h3>

Volume is the amount of space occupied by an object or a plane figure.

To calculate the volume of the material that must be used to make a star with the mass of the sun, we use the formula below.

Formula:

  • D = m/V............ Equation 1

Where:

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  • V = Volume of the material

Make V the subject of the equation

  • V = m/D........... Equation 2

From the question,

Given:

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Substitute these values into equation 2

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Hence, The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

Learn more about volume here: brainly.com/question/1972490

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