Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.
Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Starting position at x = 16m
Ending position at x = -25m
Time of flight = 4s
Unknown:
Distance flown = ?
Displacement = ?
Speed = ?
Velocity = ?
Solution:
To find the distance flown, we should understand that the body is moving on the x - plane;
So distance = 16 + 25 = 41m
Displacement is 41m to the left or -x axis
Speed is the distance divided by the time taken;
Speed = =
= 10.25m/s
Velocity is 10.25m/s along -x axis
Answer:
The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.
Explanation:
Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:
At the top of a round hill
At the foot of a round hill