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3 years ago

PLEASE HELP!!!!!!! I have 2 of these science questions!!!!

Physics

2 answers:

Stells [14]3 years ago

7 0

Answer:

1. Flammability.

2.Endothermic.

3. I don't know.

4. Kg is a unitof mass.

Explanation:

Trust me, I googled these.

AleksandrR [38]3 years ago

6 0

Answer:1-B

2-B( not sure)

4- C

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In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s

DaniilM [7]

Answer:

a. $i=4760 kg*m/s$

b. $D_U= 1.11 m$

Explanation:

F= 120,000N

Kinetic energy @ impact = 120,000*depth

$K_E= (1/2)*85kg*(56m/s)^2$

$K_E=133280 J$

$D_U= \frac{133280J}{120000N} = 1.11 m$

The momentum is equal to the impulse on him from the snow so:

$p=m*v$

$p=85kg*56m/s$

$i=4760 kg*m/s$

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3 years ago

A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the

Vinvika [58]

Answer: $0.25\ kg-m^2$

Explanation:

Given

mass of Point object $m=1 kg$

Distance $r=0.5 m$

Since mass is moving in circular path therefore every time mass is at distance of r from center .

Also Moment of Inertia tells about the distribution of mass over the given region with respect to center of mass.

Therefore $I=mr^2$

$I=1\times 0.5^2$

$I=0.25\ kg-m^2$

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3 years ago

Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat

Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

K.E_2 = ⅓E_k

So, the new kinetic energy is one third of the E_k

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Answer:

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Answer:

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