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3 years ago

8

1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is

the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m

1 answer:

patriot [66]3 years ago

4 0

Answer:

i think its going to be 150 because its half of 300

Explanation:

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According to my assumptions,the answer closest to the perfection is :

c. they show royalty instead of peasants.

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4 years ago

A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision. Corrective lenses are available in inc

tino4ka555 [31]

Answer:

P = 3.5 D

Explanation:

As we know that convex lens is to be used to make the near point of eye to be correct

So we will have

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

here we have

$d_i = 2.3 m = 230 cm$

$d_o = 25 cm$

now plug in all values into the formula

$-\frac{1}{230} + \frac{1}{25} = \frac{1}{f}$

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3 years ago

Si usted trata de contrabandear lingotes de oro llenando su mochila, cuyas dimensiones son de 56 cm * 28 cm * 22 cm, ¿cuál sería

kati45 [8]

Answer:

Mass, m = 665.77 kg

Explanation:

The question says that "If you try to smuggle gold bars by filling your backpack, whose dimensions are 56 cm * 28 cm * 22 cm, what would be its mass? "

The dimension of gold bar is 56 cm×28 cm×22 cm

We know that the density of gold is 19.3 g/cm³

The mas per unit volume of a material is called its density. It can be given by :

$d=\dfrac{m}{V}\\\\m=d\times V\\\\m=(19.3\ g/cm^3)\times (56\times 28\times 22\ cm^3)\\\\m=665772.8\ g\\\\m=665.77\ kg$

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3 years ago

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Answer:

The spring constant is 215.6 N/m.

Explanation:

Given that,

Distance = 39 cm

Compresses length = 29 cm

Mass = 2.2 kg

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$x=l-l'$

Put the value into the formula

$x=39-29=10\ cm$

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Using formula of restoring force

$F=kx$

$k=\dfrac{mg}{x}$

Where, F = force

x = distance

Put the value into the formula

$k=\dfrac{2.2\times9.8}{10\times10^{-2}}$

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Answer:

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