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bekas [8.4K]
1 year ago
15

An organic molecule consists of carbon, hydrogen, oxygen, nitrogen, and sulfur; the molecule is probably an amino acid. carbon d

ioxide. a monosaccharide. a triglyceride (fat). a phospholipid
Chemistry
1 answer:
ddd [48]1 year ago
8 0

Answer:

A typical organic molecule that contains carbon hydrogen oxygen nitrogen and sulfur will be an amino acid.

Explanation:

Amino acid is the basic protein unit composed of the amino group, carboxylic group, and an alkyl group (which is specific for every amino acid). The R group or alkyl group is what gives the amino acid its identity. For example, the amino acid will be glycine if a Hydrogen atom is attached in place of the R group, and alanine if somehow the R group is replaced by a methyl group. Cystine is a typical example of an amino acid in which carbon, hydrogen oxygen, nitrogen, and sulfur are present. The structure of cystine is given below.

You can also get help from the following answer:

brainly.com/question/14583479

#SPJ4

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Tems11 [23]
B. A solar cycle usually lasts 11 years.
4 0
3 years ago
Screen of monitors and televisions are made by ?
kati45 [8]

Answer:

C

Explanation:

This is a correct answer i think soo

8 0
3 years ago
Read 2 more answers
How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3
8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

\frac{3}{1} =\frac{y}{0.02256} \\

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0
3 years ago
0.53g of acetanilide was subjected to kjeldahl determination and the ammonia produced was collected in 50cm3 of 0.50M of h2so4.o
Lady bird [3.3K]

Answer:

10.57% of N in acetanilide

Explanation:

All nitrogen in the sample is converted in NH₃ in the Kjeldahl determination. The NH₃ reacts with H₂SO₄ as follows:

2NH₃ + H₂SO₄ → 2NH₄⁺ + SO₄²⁻

The acid in excess in titrated with Na₂CO₃ as follows:

Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂

To solve this question we must find the moles of sodium carbonate = Moles of H₂SO₄ in excess. The added moles - Moles in excess = Moles of sulfuric acid that reacts:

<em>Moles Na₂CO₃ anf Moles H₂SO₄ in excess:</em>

0.025L * (0.05mol / L) = 1.25x10⁻³ moles Na₂CO₃ / 0.01360L =

0.09191M * 0.250L = 0.0230 moles H₂SO₄ in excess.

<em>Moles H₂SO₄ added:</em>

0.050L * (0.50mol / L) = 0.0250 moles H₂SO₄ added

<em>Moles that react:</em>

0.0250 moles - 0.0230 moles = 0.0020 moles H₂SO₄

<em>Moles of NH₃ = Moles N:</em>

0.0020 moles H₂SO₄ * (2mol NH₃ / 1mol H₂SO₄) = 0.0040 moles NH₃ = Moles N

<em>mass N and mass percent:</em>

0.0040 moles N * (14g / mol) = 0.056gN / 0.53g * 100 =

<h3>10.57% of N in acetanilide</h3>
7 0
3 years ago
What volume is equivalent to 12.0 m^3?
anzhelika [568]

1.2 x 10^10 mm^3 is equivalent to 12.0 m^3

8 0
3 years ago
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