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bekas [8.4K]
1 year ago
15

An organic molecule consists of carbon, hydrogen, oxygen, nitrogen, and sulfur; the molecule is probably an amino acid. carbon d

ioxide. a monosaccharide. a triglyceride (fat). a phospholipid
Chemistry
1 answer:
ddd [48]1 year ago
8 0

Answer:

A typical organic molecule that contains carbon hydrogen oxygen nitrogen and sulfur will be an amino acid.

Explanation:

Amino acid is the basic protein unit composed of the amino group, carboxylic group, and an alkyl group (which is specific for every amino acid). The R group or alkyl group is what gives the amino acid its identity. For example, the amino acid will be glycine if a Hydrogen atom is attached in place of the R group, and alanine if somehow the R group is replaced by a methyl group. Cystine is a typical example of an amino acid in which carbon, hydrogen oxygen, nitrogen, and sulfur are present. The structure of cystine is given below.

You can also get help from the following answer:

brainly.com/question/14583479

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Pls help me for this one :) is hard for me thx
zvonat [6]

Answer:

protein

Explanation:

that the answer

8 0
3 years ago
Read 2 more answers
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
In the reaction K2CrO4 (aq) + PbCl2 (aq) 2KCl (aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction
tankabanditka [31]
The answer is 24 grams                       
6 0
3 years ago
When ash, cinders, and bombs build up in a steep pile around a volcano’s vent, the result is a
Verdich [7]
Im pretty sure a cinder-cone volcano 
8 0
3 years ago
In the first distillation this week, which component of the original solvent mixture makes the larger contribution to the vapor
Olenka [21]

In the first distillation this week, Hexane from the original solvent makes a larger contribution to the vapor pressure of the mixture.

In between hexane and toluene, the hexane will have more vapor pressure contribution in the solution. The boiling point of hexane is much lower than toluene. Therefore, it will evaporate easily at low temperatures and start exerting pressure on the solution.

Hence between hexane and toluene, because of more vapor pressure of hexane and lower boiling point, it will easily evaporate and exerts pressure.

Therefore, from the original solvent, hexane makes a larger contribution to the vapor pressure of the mixture.

To learn more about vapor pressure and hexane, visit: brainly.com/question/28206662

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7 0
1 year ago
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