On the cumulative Report, it would be much easier to read for the patients if the ranges in parentheses were tabbed over from the actual result instead of printing directly one space after the result.
<u>Answer;</u>
= 0.422 M
<h3><u>Explanation;</u></h3>
Molarity or concentration is the number of moles of a solute in 1 liter of a solution.
Therefore; Molarity = n/V ; where n is the number of moles and V is the volume of the solution in L.
Number of moles = Mass/molar mass
= 289 g/342.2965g/mol
= 0.844 Moles
Therefore;
Molarity = 0.844 moles/ 2L
= 0.422 M
Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.
Hence, moles of 
= 
.......... (1)
As, No. of moles = 
Hence, moles of 
will be calculated as follows.
No. of moles =
= 
(molar mass of is 255.415 g/mol)
= 
Moles of = 
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity = 
= 
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.
Answer:
d
Explanation:
kinetic energy is transferred into movement.
When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.
- Propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
- The Bromine which is present in the 2-bromopropane is removed through hydrogenation and combines with the sodium metal which results in the production of propane and sodium bromide.
- So we can conclude that propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
Learn more about 1-bromo propane here: brainly.com/question/25597694
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