Answer:
[H₂] = 1.61x10⁻³ M
Explanation:
2H₂S(g) ⇋ 2H₂(g) + S₂(g)
Kc = 9.30x10⁻⁸ =
First we <u>calculate the initial concentration</u>:
0.45 molH₂S / 3.0L = 0.15 M
The concentrations at equilibrium would be:
[H₂S] = 0.15 - 2x
[H₂] = 2x
[S₂] = x
We <u>put the data in the Kc expression and solve for x</u>:
We make a simplification because x<<< 0.0225:
x = 8.058x10⁻⁴
[H₂] = 2*x = 1.61x10⁻³ M
Answer: The fusion of hydrogen to form helium
Explanation:
Answer:
In the given voltaic cell, the reaction occurring at cathode :
Explanation:
A voltaic cell is an electro-chemical cell which converts chemical energy into electrical energy. It has two electrodes :
- Anode : Where oxidation occurs , that is loosing of electrons.
- Cathode : Where reduction occurs, that is gaining of electrons.
In the given voltaic cell, the reaction occurring at anode:
In the given voltaic cell, the reaction occurring at cathode :
These metals are silver and soft, much like the alkali metals of Group 1. These metals also react with water, though not as vigorously. Beryllium, interestingly, does not react with water. Each alkaline earth metal has two valence electrons.
Hope this helps :)