-14x + 15y = 15
-14x + 14x + 15y = 14x + 15
15y = 14x + 15
15 15
y = ¹⁴/₁₅x + 1
-21x - 20y = -10
-21x - 20(¹⁴/₁₅x + 1) = -10
-21x - 20(¹⁴/₁₅x) - 20(1) = -10
-21x - 18²/₃x - 20 = -10
-39²/₃x - 20 = -10
+ 20 + 20
-39²/₃x = 10
-39²/₃ -39²/₃
x = ⁻³⁰/₁₁₉
y = ¹⁴/₁₅x + 1
y = ¹⁴/₁₅(⁻³⁰/₁₁₉) + 1
y = ⁻²⁸/₁₁₉ + 1
y = ⁹¹/₁₁₉
(x, y) = (⁻³⁰/₁₁₉, ⁹¹/₁₁₉)
Solution for part A is where the red line and the red line meet, (2,-1)
solution for part B: any point on the blue red line is a solution. (2, -1), (0, 3), (3, -3), (-2, 7)
solution for part C is where the green curve and the blue line meet, (0,3)
Answer:
1548 lb
Step-by-step explanation:
Let the truck's weight be w.
Then (1/3)w = 516 lb
Solve for the truck's weight by multiplying both sides of this equation by 3:
w = 1548 lb (Answer B)
Answer:
Twa
Step-by-step explanation:
Kekeiejkdkddkskkkdkdkd
Answer:
m∠ABC = 119° and DC = 105 feet
Step-by-step explanation:
For better understanding of the solution see the attached figure of the trapezium ABCD :
m∠BCD = 61°
By using the property, Sum of interior opposite angles in a trapezium is supplementary ⇒ m∠BCD + m∠ABC = 180°
⇒ m∠ABC = 180° - 61°
⇒ m∠ABC = 119°
Now, to find length of DC,
Draw a perpendicular BE on CD ⇒ CD = DE + EC
AB = DE
⇒ DE = 80 feet
In ΔBEC, By using Pythagoras theorem
EC² = BC² - BE²
⇒ EC² = 65² - 60²
⇒ EC = 25 feet
Hence, DC = 80 + 25
= 105 feet