In my estimations you have a triangle with 2 angles and an altitude or height. You have to find the base of the triangle in order to find the area. I set up the triangle and sine the 60 degree angle was bisected I know that the vertex angle is 30 in my right triangle. I used the tangent ratio of 30 to find the base of that triangle and then multiplied it by 2 to get that the whole base measure is 27.71281292. Then I multiplied it by the height I was given of 24 and divided the whole mess in half to get the area. 332.553 units squared.
That's a tricky one because x is a function of y but y isn't a function of x.
(x, x²) is a perfectly good relation.
I'm not totally sure but I'd
Answer: B
D is the other answer that may be accepted but knowing teachers, I'd go with B.
5x^2-45=0
<em>*Add 45 to both sides*</em>
5x^2=45
<em>*Divide both sides by 5*</em>
x^2=9
<em>*Take the square root of both sides*</em>
x=+/-9
Hope this helps!!
The
<u>correct diagram</u> is attached.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.