Question

Q/C A man claims that he can hold onto a 12.0 -kg child in a head-on collision as long as he has his seat belt on. Consider this man in a collision in which he is in one of two identical cars each traveling toward the other at 60.0m/h relative to the ground. The car in which he rides is brought to rest in 0.10s . (a) Find the magnitude of the average force needed to hold onto the child.

Answer 1

Average force $F_{avg}$=3216N

How this is calculated?

Given:

   $m=12kg$

   $v_i=60mi/h=26.8m/s\\v_f=0\\t=0.10s$

We know that,

I=Δp(according to impulse momentum theorem)

I= $F_{avg}$Δt

So,$F_{avg}$Δt=Δp

               $=p_f-p_i\\=mv_f-mv_i$

        $F_{avg}=\frac{mv_i}{delta t} \\\\ =\frac{12*26.8}{0.1}$=3216N

What is the average force?

• The average force is the force exerted by some object moving at some defined rate of speed i.e. velocity for a defined period of time.
• The word average here is used to indicate that this is not an instantaneous or precisely measured velocity.

To know more about  average force, refer:

brainly.com/question/18652903

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