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4 years ago

1. What are advantages and disadvantages of using a solar cooker compared to other meanings of cookings?

Physics

1 answer:

Brums [2.3K]4 years ago

8 0

Answer:

The biggest advantage of Solar cookers is their eco-friendliness. By exploitation one you’ll decrease your dependence on gas or electricity, cut back your carbon footprint, and save on fuel and therefore the value of fuel on running home appliances. change of state with star cookers clearly needs daylight, that makes it troublesome to use throughout winter months and on rainy days. change of state conjointly takes a considerably longer time compared to traditional strategies. Users should schedule their change of state time and maximize the employment of daylight. As a result, preparation should begin early within the morning in order that the food may be placed in the cooking utensil by noontide.

Explanation:

Hope this helps

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The ratio of the lift force L to the drag force D for the simple airfoil is L/D = 10. If the lift force on a short section of th

Yuri [45]

Answer:

$R=64.32\ lb\\\\\theta=84.3\°$

Explanation:

Given:

Ratio of lift force to drag force is, $\frac{L}{D}=10$

Lift force on a short section is, $L=64\ lb$

Magnitude of resultant, $R= ?$

The angle of 'R' with the horizontal is, $\theta=?$

We know that, lift force and drag are at right angles to each other. So, the resultant can be computed using Pythagoras theorem.

For calculating 'R', we first compute drag force 'D'.

As per question:

$\frac{L}{D}=10\\\\D=\frac{L}{10}=\frac{64\ lb}{10}=6.4\ lb$

Now, the magnitude of resultant 'R' is given as:

$R=\sqrt{L^2+D^2}$

Plug in the given values and solve for 'R'. This gives,

$R=\sqrt{64^2+6.4^2}\\\\R=\sqrt{4096+40.96}\\\\R=\sqrt{4136.96}=64.32\ lb$

Therefore, the magnitude of the resultant force 'R' is 64.32 lb.

Now, the angle $\theta$ is given as the arctan of the ratio of the lift and drag force.

Therefore,

$\theta=\tan^{-1}(L/D)\\\\\theta=\tan^{-1}(10)\\\\\theta=84.3\°$

Therefore, the angle made with the horizontal is 84.3°.

6 0

3 years ago

A vector has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A makes with the x-axis?a. 67.4ob. 32.6oc. 22.

antoniya [11.8K]

Answer:

C.22.6°

Explanation:

Ax = ACosθ,

A = Ax/Cosθ .....equ1

Ay = Asinθ,

A= Ay/sinθ .....equ 2

equate equation 1 and 2.

Ax/Cosθ = Ay/sinθ

Ax = 12.0 m, Ay= 5.00 m

12/Cosθ = 5/sinθ

θ = 22.6°

5 0

3 years ago

You've been called in to investigate a construction accidentin

KengaRu [80]

Answer:

57300 N

Explanation:

The container has a mass of 5300 kg, the weight of the container is:

f = m * a

w = m * g

w = 5300 * 9.81 = 52000 N

However this container was moving with more acceleration, so dynamic loads appear.

w' = m * (g + a)

w' = 5300 * (9.81 + 1) = 57300 N

The rating for the cable was 50000 N

The maximum load was exceeded by:

57300 / 50000 - 1 = 14.6%

5 0

3 years ago

A particle of unit mass moves in a potential V(x)= ax^2+b/x^2 . Where a and b are constnts. Calcuate the angular frequency of sm

Sholpan [36]

Answer:

Explanation:

Given

Potential Energy is given by

$U(x)=ax^2+\frac{b}{x^2}$

And Force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

Particle will be at equilibrium when Potential Energy is either minimum or maximum

$F=-\left ( 2ax-\frac{2b}{x^3}\right )$

i.e. $ax=\frac{b}{x^3}$

$x_0=(\frac{b}{a})^{0.25}$

So angular Frequency of small oscillation is given by

$\omega =\sqrt{\frac{U''(x)}{m}}$

for $m=1$

we get $\omega =\sqrt{\frac{U''(x_0)}{1}}$

$U''(x_0)=2a+6a= 8a$

$\omega =\sqrt{8a}$

4 0

3 years ago

A spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?

vitfil [10]

Answer:

b. 0.45 meters

Explanation:

Given the following data;

Spring constant, k = 330 N/m

Force = 150 N

To find the extension of the spring;

Mathematically, the force exerted on a spring is given by the formula;

Force = spring constant * extension

Substituting into the formula, we have;

150 = 330 * extension

Extension, e = 150/330

Extension, e = 0.45 meters

7 0

3 years ago