These answers are very good. I made a 95% by using this as my answer key, but unfortunately, one of these is wrong. I don't know which one, all I know is that I got 19/20. Just wanted to throw that out there. :-) Good job, Sadaqasalaam3. And thank you.
0.15 m/s East
If you follow the equation a=vf-vi/t, you'll discover that subtracting the final velocity, 0.25 m/s, by the initial velocity, 0.10 m/s, and divide by zero, (bc there was no given time) the answer is 0.15 m/s East
Answer:
The correct answer is A and B
Explanation:
Light is part of the spectrum of electromagnetic energy along with radio waves, microwaves, infrared, visible light, ultraviolet, X rays and Gamma rays.
Radio waves and microwaves lie on one end of the spectrum, the longer end of electromagnetic energy.
X rays and Gamma rays have very short wavelengths .
I hope it helps!
Answer:
a) F=20287.22N
b) t=2*10^-4s
Explanation:
E=1/2*m*v^2=0.5*7.8*10^-3kg*(530m/s)^2=1095.51J
The frictional force's work must be equal than the energy to stop the bullet.
So: W=F*d=F*0.054m=1095.51J, F=20287.22N
Considering the frictional force is constant, the bullet moves with constant aceleration.
a=F/m=20287.22N/7.8*10-2kg=2.6*10^6m/s^2
then d(t)=Vt-1/2*a*t^2,
5.4*10^-2m=530m/s*t-1.3*10^6m/s^2*t^2
I will calculate the time using the cuadratic formula:

with a=1.3*10^6, b=-530, c=5.4*10^-2
t=2*10^-4s
Answer: 1.85 C
Explanation:
Given
charges on the conductors are
and 
They are connected by a conducting wire for a short period of time and then disconnected. During this time charge flow from the wire and net charge becomes 
This charge will be equally distribute among the two conductors i.e. 1.85 C on each conductor.