What do you mean? I'm confused... You need to put the rest of the question
When hard stabilization structures such as groins are used to stabilize a shoreline, the change in the longshore current results <u>deposition of sediment. </u>
On the upcurrent side of the barrier, sediment is deposited as the longshore current slows.
What is Hard stabilization?
- Hard stabilization is the prevention of erosion through the use of artificial barriers.
- Other hard stabilization structures, such as breakwaters and seawalls, are built parallel to the beach to protect the coast from the force of waves.
- Hard stabilization structures, such as groins, are built at right angles to the shore to prevent the movement of sand down the coast and maintain the beach.
- These constructions are made to last for many years, but because they detract from the visual splendor of the beach, they are not always the ideal answer.
- Additionally, they affect the habitats and breeding sites of native shoreline species, interfering with the ecosystem's natural processes.
Learn more about the Hard stabilization with the help of the given link:
brainly.com/question/16022736
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My teacher said 36m when I asked her
Answer:
The dimension of the nullspace of T = 4
Explanation:
The rank/dimension theorem is explains that:
Suppose V and W are vector spaces over F, and T:V → W is linear. If V is finite dimensional, then
nullity(T) + rank(T) = dim(V).
rank(T) = dimension of T = dim(T) = dim(W) = 7
nullity(T) = dimension of the nullspace of T = dim(T) = ?
dim(V) = 11
nullity(T) = dim(V) - dim(T) = 11 - 7
nullity(T) = 4.
