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1 year ago

If 50 one-cent coins were stacked on top of

Mathematics

1 answer:

Sedbober [7]1 year ago

7 0

To make 8 inch tall column approximately 61 coins required.

Given,

Total one cent coins stacked on top of each other in a column = 50

Height of column = 378 inches

Approximate height of one coin = ( 50 / 378)

= 0.132 inches

To make an 8 inches tall stack No of coins required will be:

Number of coins required = ( total height / height of one coin )

= ( 8 / 0.132 )

= 60.60

≅ 61 coins

To make 8 inch tall column approximately 61 coins required.

Learn more about coins here: brainly.com/question/11677207

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It takes 45 minutes for 4 people to paint 5 walls. How many minutes does it take 6 people to paint 4 walls?

vovangra [49]

45/5 = 9minutes/wall = 1wall/9minute/4 people = (1/36) per minute per person

(1/36)*6 = 1/6 wall per minute per 6 people * 24 = 4 walls in 24 minutes

24 Minutes total

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2 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

3/4 of a piece of metal has a mass of 15kg.what is the mass of 2/5 of the piece of metal

olga2289 [7]

3/4=15
let,
total mass is x
x=4×15/3
=20 kg
so, total mass = 20 kg

=2×20/5
=2×4
=8 kg

Hope this helps!

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3 years ago

What value of x makes this true 1.5x=120?

Debora [2.8K]

Answer: 80

Step-by-step explanation:

x.3/2 = 120

x = 120.2/3

x=80

5 0

3 years ago

Read 2 more answers

Question 5 (2) x cube - 3x square 9x - 5

kakasveta [241]

Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.

Do you mean Question #5? By (2) x cube, do you mean 2x^3?

I strongly suggest that you use lots of parentheses ( ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.

If only you'll clear this up, I'd be happy to help.

I will assume that your post is 2x^3 - 3(9x-5)^2.

Then 2x^3 - 3(81x - 90x + 25). Does this have any resemblance to what you wanted me to see in your post?

3 0

3 years ago