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1 year ago

Regression is a statistical technique developed by blaise pascal. a. false. b. true.

1 answer:

4 0

Blaise Pascal invented the statistical method known as regression. False. The author learned through the reading that adding a bathroom increases home prices more than adding a bedroom does.

What does a statistical regression mean?

A statistical method called regression links a dependent variable to one or more independent (explanatory) variables.
A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.

What does regression mean?

Regress, from which the word "regression" is derived, means "to go back" in Latin (to something).
Regression is the method that, in this way, enables "going back" from muddled, challenging-to-interpret data to a clearer and more understandable meaningful model.

Learn more about regression

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Use square roots to solve the equation x2 = −25 over the complex numbers. Select all the solutions.

Nezavi [6.7K]

Answer:

E and A

Step-by-step explanation:

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3 years ago

Sean has to face a big problem but he becomes stronger as a result which saying best summarizes the change in Sean?

kkurt [141]

Answer: D. every cloud has a silver lining

The cloud represents a dark, scary, or sad moment. This is in contrast to the sun which metaphorically represents energy and happiness. The cloud sometimes covers up the sun to cover up those happy moments so to speak.

Despite the cloud being present, there's a silver lining to the cloud which represents some positive aspect a person didn't expect to happen. In this case, the problem allows Sean to get stronger. So this is an opportunity for his growth.

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3 years ago

roberto has 12 tiles. each tile is 1 square inch. he will arrange them into a rectangle and glue 1-inch stones around the edge.

LUCKY_DIMON [66]

To answer this you will need to determine which area made with the 12 square tiles would give the shortest perimeter.

Think of all the combinations to get 12 square inches
1x12, 2x6, and 3x4. The perimeters of these are 26 in, 16 in, and 14 in.

You should arrange your tiles using the 3 x 4 option. You would need 14 stones.

3 0

2 years ago

Evaluate the integral, show all steps please!

Aloiza [94]

Answer:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x$

Rewrite 9 as 3² and rewrite the 3/2 exponent as square root to the power of 3:

$\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x$

Integration by substitution

$\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}$

$\textsf{Let }x=3 \sin \theta$

$\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}$

Find the derivative of x and rewrite it so that dx is on its own:

$\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta$

$\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta$

Substitute everything into the original integral:

$\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}$

Take out the constant:

$\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta$

$\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}$

$\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$