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OverLord2011 [107]
1 year ago
7

The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?

Mathematics
1 answer:
aivan3 [116]1 year ago
5 0

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

Learn more about slope of perpendicular lines on:

brainly.com/question/1362601

#SPJ1

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f(x)=x^2-2x-8;\ g(x)=\dfrac{1}{4}x-1\\\\f(x)=g(x)\iff x^2-2x-8=\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4x^2-8x-32=x-4\qquad\text{subtract x from both sides}\\\\4x^2-9x-32=-4\qquad\text{add 4 to both sides}\\\\4x^2-9x-28=0\\\\4x^2-16x+7x-28=0\\\\4x(x-4)+7(x-4)=0\\\\(x-4)(4x+7)=0\iff x-4=0\ \vee\ 4x+7=0\\\\x=4\ \vee\ 4x=-7\\\\\boxed{x=4\ \vee\ x=-\dfrac{7}{4}}

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