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1 year ago

The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?

Mathematics

1 answer:

aivan3 [116]1 year ago

5 0

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

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Which of the following is true regarding the solution to the logarithmic equation below? log subscript 2 baseline (x 11) = 4. x

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<h3>Data obtained from the question </h3>

Log₂ (x + 11) = 4
Value of x =?

<h3>How to determine the value of x </h3>

Log₂ (x + 11) = 4

x + 11 = 2⁴

x + 11 = 16

Collect like terms

x = 16 – 11

x = 5

<h3>**Check** </h3>

Log₂ (x + 11) = 4

x = 5

Log₂ (5 + 11) = 4

Log₂ 16 = 4

Find the value of Log₂ 16

Log₂ 16 = n

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Log₂ 16 = 4

Therefore, the correct answer to the question is:

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Complete question

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