Question

consider the equilibrium that exists for a saturated aqueous solution of pbcl2. pbcl2s⇄pb2 aq 2 cl-aq which expression gives the solubility product constant ksp for pbcl2 if the [pb2 ]

Answer 1

The solubility product is 4n³.

The equilibrium constant for a solid's dissolving into an aqueous solution is called the solubility product constant. It is represented as K(sp).

A solution is said to be saturated when it has dissolved all of the solutes it can. At a certain temperature, no additional solute can dissolve in a saturated solution.

Consider the equilibrium for a saturated PbCl₂ aqueous solution.

PbCl₂(s) ⇄⇄ Pb₂ (aq) + 2Cl⁻ (aq)

The equilibrium constant for the dissociation reaction of the PbCl₂ solution is:

K(sp) = [Pb²⁺] [Cl⁻]²

Now, [Pb²⁺] = n mol/L

In the solution, there is one-mole Pb²⁺ and two moles of Cl⁻ .

Therefore,

[Cl⁻] = 2n mol/L

So, the equilibrium constant for the dissociation reaction will be:

K(sp) = [Pb²⁺] [Cl⁻]²

K(sp) = n × (2n)²

K(sp) = n × 2n × 2n

K(sp) = 4n³

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