Answer:
The answer to your question is molality = 0.34
Explanation:
Data
mass of NaBr = 14.57 g
mass of water = 415 g.
molality = ?
Process
1.- Calculate the molar mass of NaBr
NaBr = 23 + 80 = 103 g
2.- Calculate the moles of NaBr
103 g of NaBr ------------------ 1 mol
14.57 g of NaBr --------------- x
x = (14.57 x 1) / 103
x = 14.57 / 103
x = 0.141 moles
3.- Calculate the molality
molality = moles / volume
-Substitution
molality = 0.141 / .415
-Result
molality = 0.34
Answer:
b
Explanation:
because it has gained an electron
The force exerted on the parked car by the moving car is –30000 N
To solve this question, we'll begin by calculating the deceleration of the moving car. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.5 s
<h3>Deceleration (a) =?</h3>
<h3>a = - 20 m/s</h3>
Finally, we shall determine the force exerted by the moving car on the parked car. This can be obtained as follow:
Mass of moving car (m) = 1500 Kg
Acceleration (a) = - 20 m/s
<h3>Force (F) =.?</h3>
F = ma
F = 1500 × (-20)
<h3>F = -30000 N</h3>
NOTE: The negative sign indicate force is in opposite direction to the parked car.
Therefore, the force exerted on the parked car by the moving car is –30000 N
Learn more: brainly.com/question/15430805
Answer:
96 g of O
Explanation:
Mg(OH)₂ → Magnesium hydroxide
Molar mass → 24.3g/mol . 1 + 16g/mol . 2 + 1g/mol . 2 = 58.3 g/mol
We determine the moles of hydroxide → 175 g . 1mol/58.3g = 3 moles
Let's make some rule of three:
In 100 g of compound we have 54.87 g of O
In 58.3 g of compound we may have (58.3 . 54.87) / 100 = 32 g
So, 1 mol of hydroxide has 32 g of oxygen
3 moles of hyroxide may have (3 .32)/1 = 96 g of O
