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Vlada [557]
3 years ago
10

During a laboratory experiment, you discover that an enzyme-catalyzed reaction has a ∆G of -20 kcal/mol. If you double the amoun

t of enzyme in the reaction, what will be the ∆G for the new reaction?
Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer:

dG will be the same -20 kcal/mol

Explanation:

The dG can be expressed in terms of the G(products) - G(reactants). If the amount of enzyme is doubled the Gibbs energy of the reactants and products will be the same, so the substraction dG has the same value

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When 1 mole of H2(g) reacts with F2(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved H2(g) + F
topjm [15]

Answer: The reaction is exothermic. The value of q is  -542 kJ.

Explanation:

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and  for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and  for the reaction comes out to be negative.

Thus H_2(g)+F_2(g)\rightarrow 2HF(g) evolves heat , it is exothermic in nature. The value of q is -542kJ.

7 0
3 years ago
2. Use the Henderson-Hasselbalch equation to estimate the pH of a buffer solution that is composed of 20 mL of 10 M sodium forma
Mkey [24]

Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

pH=pKa+log[\frac{[salt]}{[acid]}

Given:

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concentration of acid = concentration of formic acid = 1 M

concentration of salt =  concentration of sodium formate = 10 M

pH=3.75+log[\frac{10}{1}]=3.75+1=4.75

pH of buffer =4.75

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3 years ago
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Diano4ka-milaya [45]

Answer:

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5 0
2 years ago
At STP , how many molecules of nitrogen gas are in 2.24 L?
Oksanka [162]

Explanation:

At STP ,2.24 L contain 0.1 mole of N²

<h2>So,No. of molecules of N2 = 6.022*10²²</h2>
7 0
2 years ago
Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 14.0 atm. Calculate the work, w , if the gas exp
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