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Vlada [557]
3 years ago
10

During a laboratory experiment, you discover that an enzyme-catalyzed reaction has a ∆G of -20 kcal/mol. If you double the amoun

t of enzyme in the reaction, what will be the ∆G for the new reaction?
Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
7 0

Answer:

dG will be the same -20 kcal/mol

Explanation:

The dG can be expressed in terms of the G(products) - G(reactants). If the amount of enzyme is doubled the Gibbs energy of the reactants and products will be the same, so the substraction dG has the same value

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For this reaction: ΔG⁰>0.

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ΔG° indicates that all reactants and products are in their standard states.

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If K < 1, than ΔG° > 0.

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