First, is to solve the molar mass of the herbicide, with a formula
<span>C3H8NO5P
C3 = 12 ( 3 ) = 36
H8 = 1 ( 8 ) = 8
N = 14
O5 = 16 ( 5 ) = 80
P = 31
so in total the molar mass of </span><span>C3H8NO5P is 36 + 8 + 14 + 80 + 31 = 169 g/mol
number of moles = 783.5 g ( 1 mol / 169 g)
number of moles = 4.64 mol </span><span>C3H8NO5P</span>
Answer:
See image attached and explanation
Explanation:
The stratospheric ozone layer is very important in absorbing high-energy ultraviolet radiation that is harmful to living systems on earth. The concentration of ozone in the stratosphere is determined by both thermal and photochemical pathways for its decomposition. Nitric oxide, NO, is a trace constituent in the stratosphere that reacts with ozone to form nitrogen dioxide, NO2, and the diatomic oxygen molecule. The nitrogen-oxygen bond in NO2 is relatively weak. When an NO2 molecule encounters an oxygen atom, it transfers an oxygen, forming O2 and NO. The chemical reactions involved are formations of NO2 following by reaction of NO2 with atomic oxygen for form NO and O2. The sum of both reactions show that the overall reaction is simply the reaction of ozone with atomic oxygen to form two molecules of molecular oxygen. Hence, NO only serves as a catalyst, it does not undergo a permanent change itself.
the 1st one is balanced, the 2nd isn't (the number of Mg differs from left 1 to right 2).
The third is also not balanced, 2 F left,2*3=6 on the right
Clearly H2 is in gaseous state as could be seen from (g) written with it which tells state of the product
The required mass of calcium bromide is 35.98 grams.
<h3>What is molarity?</h3>
Molarity is any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V, where
- M = molarity = 4M
- V = volume = 45mL = 0.045L
Moles will be calculated by using the above equation as:
n = (4)(0.045) = 0.18 mole
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g
Hence required mass of CaBr₂ is 35.98 grams.
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