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Anarel [89]
2 years ago
12

The third term in a geometric sequence is 96 and the sixth term is 6144

Mathematics
1 answer:
dexar [7]2 years ago
7 0

The recursive formula for a geometric sequence is:

a_{n} =r(a_{n} -1) , n\geq 2.

According to the statement

we have to find that the recursive formula for geometric sequence.

So, For this purpose, we know that the

Geometric Progression (GP) is a type of sequence where each succeeding term is produced by multiplying each preceding term by a fixed number, which is called a common ratio.

And from the given information:

The third term in a geometric sequence is 96 and the sixth term is 6144.

it means

a_{3} = 96. and the a_{6} = 6144.

we know that the there is a one ratio which is same in all the two nubers between them.

And that's why

The recursive formula for a geometric sequence with common ratio r is:

a_{n} =r(a_{n} -1) , n\geq 2.

Hence, The recursive formula for a geometric sequence is:

a_{n} =r(a_{n} -1) , n\geq 2.

Learn more about Geometric Progression here

brainly.com/question/1509142

#SPJ9

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A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 1:4.
schepotkina [342]

Let point C has coordinates (x_C,y_C). Consider vectors

\overrightarrow{AB}=(x_B-x_A,y_B-y_A)=(8-9,6-9)=(-1,-3),\\ \\\overrightarrow{BC}=(x_C-x_B,y_C-y_B)=(x_C-8,y_C-6).

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