tThe time taken by the slower train to pass the driver of the faster one is 24 sec.
Given that, two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively.
We need to find the time taken by the slower train to pass the driver of the faster one.
<h3>What is the relative speed?</h3>
The time after which both bodies meet = distance travelled / relative speed = dkm/ (x + y) km/hr. Now, we know that relative speed is the speed of one object with respect to another. So, if the time after which both the body moves is given, Suppose, time = t hrs.
Relative speed = (45 + 30) km/hr=75 km/hr
=(75× 5/18)m/sec
=(125/6) m/sec.
We have to find the time taken by the slower train to pass the driver of the faster train and not the complete train.
Here, distance covered = Length of the slower train.
So, the distance covered = 500 m.
Required time (500× 6/125 )=24 sec
Therefore, the time taken by the slower train to pass the driver of the faster one is 24 sec.
To learn more about the relative speed visit:
brainly.com/question/14362959.
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