Question

in a large vacuum chamber, monochromatic laser light passes through a narrow slit in a thin aluminum plate and forms a diffraction pattern

Answer 1

The correct answer is the change in width of the central maxima is of  decrease 0.02 mm and the width of diffraction pattern decreases by increase in the temperature .

T 1 =  20 c°

T 2 = 660 °C

width of central maxima in the diffration pattern  =2.04 mm

coeffificent of linear expansiion stell =12*10^-6

we know that

w =λD/d

d = λD/w

after expansion

d1= Do +(Do + A delta t)

on solving the above by putting values

d1 = Do * (1.00768)

w1 =λD/d1

w1 = 2.02 * 10^-3

change in width = w1 - w = -0.02 mm

so the witdth of central maxima decreased when to temperature is increased .

The correct  question is -

In a large vacuum chamber, monochromatic laser light passes through a narrow slit in a thin aluminum plate and forms a diffraction pattern on a screen that is 0.620 m from the slit. When the aluminum plate has a temperature of 20.0 °C, the width of the central maximum in the diffraction pattern is 2.04 mm. What is the change in the width of the central maximum when the temperature of the plate is raised to 660 °C.? Does the width of the central diffraction maximum increase or decrease when the temperature is increased?

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