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ArbitrLikvidat [17]
4 years ago
11

Which statement is true:

Physics
1 answer:
Mariana [72]4 years ago
6 0

Answer:

(A) Aircraft instruments are color coded to direct attention to operational ranges and limitations

Explanation:

The only correct statement is that Aircraft instruments are color coded to direct attention to operational ranges and limitations.

The six basic air instruments that provide a pilot with information (speed, altitude, climb/descent, attitude, heading, and turning/banking) about an aircraft are; divided into two, Pitot-static instruments and Gyroscopic instruments.

Top (Pitot-static instruments):

- Airspeed Indicator (ASI)

- Altimeter

- Vertical Speed Indicator (VSI)

Bottom (Gyroscopic instruments):

- Attitude Indicator (AI)

- Heading Indicator (HI)

- Turn Coordinator (TC)

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What is the pressure drop due to the Bernoulli Effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire
Marianna [84]

Answer:

The pressure and maximum height are 1.58\times10^{6}\ N/m^2 and 161.22 m respectively.

Explanation:

Given that,

Diameter = 3.00 cm

Exit diameter = 9.00 cm

Flow = 40.0 L/s²

We need to calculate the pressure

Using Bernoulli effect

P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho g h_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}

When two point are at same height so ,

P_{1}+\dfrac{1}{2}\rho v_{1}^2=P_{2}+\dfrac{1}{2}\rho v_{2}^2....(I)

Firstly we need to calculate the velocity

Using continuity equation

For input velocity,

Q=A_{1}v_{1}

v_{1}=\dfrac{Q}{A_{1}}

v_{1}=\dfrac{40.0\times10^{-3}}{\pi\times(1.5\times10^{-2})^2}

v_{1}=56.58\ m/s

For output velocity,

v_{2}=\dfrac{40.0\times10^{-3}}{\pi\times(4.5\times10^{-2})^2}

v_{2}=6.28\ m/s

Put the value into the formula

P_{1}-P_{2}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)

\Delta P=\dfrac{1}{2}\times1000\times(56.58^2-6.28^2)

\Delta P=1.58\times10^{6}\ N/m^2

(b). We need to calculate the maximum height

Using formula of height

\Delta P=\rho g h

Put the value into the formula

1.58\times10^{6}=1000\times9.8\times h

h=\dfrac{1.58\times10^{6}}{1000\times9.8}

h=161.22\ m

Hence, The pressure and maximum height are 1.58\times10^{6}\ N/m^2 and 161.22 m respectively.

8 0
4 years ago
The outside air pressure changes from 1.0 atm to 1.1 atm. The mass density of mercury is 13,534 kg/m3.By how much does mercury i
mezya [45]

Answer:

The mercury in the barometer rises by a height of 0.0764 m = 76.4 cm = 764 mm

Explanation:

The change in pressure is related to the density of fluid and height risen by the fluid through the relation

ΔP = ρgh

ΔP = change in pressure = P₂ - P₁ = 1.1 - 1.0 = 0.1 atm = 0.1 × 101325 Pa = 10132.5 Pa

ρ = density of the fluid = 13,534 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = height through which the mercury in barometer rises = ?

10132.5 = 13534 × 9.8 × h

h = (10132.5) ÷ (13534 × 9.8)

h = 0.0763948996 = 0.0764 m = 76.4 cm = 764 mm

Hope this Helps!!!

4 0
4 years ago
1. Two magnets are placed on a table, and they immediately move to attach to each other. Which statement is correct about the en
erma4kov [3.2K]

Answer: 1: kinetic energy and velocity are at zero when the magnets are held apart, and both increases rapidly when they are released and move together. Energy stored in the magnetic field decreases.

2: The energy stored in the system is converted to kinetic, thermal, and sound energy.

3: The energy stored in the magnetic field does not change.

4: Some of the energy stored is converted into kinetic and thermal energy.

5: Two small repelling magnets hold each other in place.

Just took the quiz all are correct! I hope this helps you! :)

3 0
3 years ago
An airplane propeller is rotating at 1900 rpm (rev/min).
alexandr1967 [171]

Answer:

See explanation

Explanation:

We have to convert to angular velocity in rads-1 as follows;

Angular velocity in rad/s = 2π/60 × 1900 rpm = 199 rad/s

Given that

angular velocity =angle turned /time taken

Time taken = angle turned/angular velocity

Converting 35° to radians we have;

35 × π/180 = 0.61 radians

Time taken = 0.61 radians/199 rad/s

Time taken = 0.0031 seconds

3 0
3 years ago
Two spherical objects are separated by a distance of 2.59 × 10-3 m. The objects are initially electrically neutral and are very
kodGreya [7K]

Answer:

Number of electrons, n = 12 electron

Explanation:

Given that,

The distance between charged spheres, d=2.59\times 10^{-3}\ m

The object experiences an electrostatic force that has a magnitude of, F=4.94\times 10^{-21}\ N

The electric force between spheres is given by :

F=\dfrac{kq^2}{d^2}

q=\sqrt{\dfrac{Fd^2}{k}}

q=\sqrt{\dfrac{4.94\times 10^{-21}\times (2.59\times 10^{-3})^2}{9\times 10^9}}

q=1.91\times 10^{-18}\ C

Let there are n number of electrons. Using quantization of electric charge we get :

q=ne

n=\dfrac{q}{e}

n=\dfrac{1.91\times 10^{-18}}{1.6\times 10^{-19}}

n = 11.93 electrons

or

n = 12 electrons

Hence, 12 electrons produce the charge on one of the objects.

4 0
3 years ago
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