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Daniel [21]
3 years ago
5

You throw a ball upward with an initial speed of 4.3 m/s. When it returns to your hand 0.88 s later, it has the same speed in th

e downward direction (assuming air resistance can be ignored). What was the average acceleration vector of the ball? Express your answer using two significant figures.
Physics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

The acceleration is -9.8 m/s²

Explanation:

Hi there!!

When you throw a ball upward, there is a downward acceleration that makes the ball return to your hand. This acceleration is produced by gravity.

The average acceleration is calculated as the variation of the speed over time. In this case, we know the time and the initial and final speed. Then:

acceleration = final speed - initial speed/ elapsed time

acceleration = -4.3 m/s - 4.3 m/s / 0.88 s

acceleration = -9.8 m/s²  

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Since the second wire is twice as far apart as the first, it will be L2 = 2L1

Let V1 and V2 be the speed of the shorter and longer wire respectively

V1 = √T/M1... 1

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Since V1 = 249m/s, M1 = m/L1 M2 = m/L2 = m/2L1

The equations will now become

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From 3,

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Dividing equation 5 by 6 we have;

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