Answer:
<em>Its true</em> i think
Explanation:
Ice wedging, as described in the passage, is an example of mechanical
weathering.
Mechanical weathering is also known as physical weathering and it
involves the breaking of rock into smaller particles without causing changes
in the chemical properties.Mechanical weathering is usually carried through
physical processes such as freezing and thawing etc.
In this scenario, we were told that water freezes, expands and presses
against the walls of the crack thereby breaking into smaller parts which is a
physical process hence mechanical weathering being present.
Read more about Mechanical weathering on brainly.com/question/458304
Answer:
649kg/m^3
Explanation:
Let p be the density of this particular object.
Formula for density:
We can substitute the givenmass and volume to find density of the object.
Therefore the density of this object is 649kg/m^3.
Answer:
The apparent weight is less than that of the real weight because of buoyancy.
Explanation:
Buoyancy is the upward thrust that is experienced by the object that is either fully or partially immersed in the object. The weight of the immersed object will be equal to the mass of the liquid that is displaced by the object. Buoyancy can be calculate based on Archimedes's Principle. Buoyancy also acts in the air, the normal force is reduced than the force of gravity. Buoyancy is the ability to float in liquid as well as in air. This floating happens when various forces acts on the opposite direction. The direction of the force will always remain upwards.
Answer:
Explanation:
a ) A force of 6 N , causes elongation of .03 m
Spring constant
k = 6 / .03
= 200 N / m
b )
Amplitude A = .04 m .
Maximum velocity of a particle in SHM
= ωA where ω is angular velocity and A is amplitude
= x A
= x A
= 20x .04 = 0.8
Maximum velocity of a particle
= 0.8 m ² s
Minimum velocity will be zero at extreme point ( at turning point )
c )
Minimum acceleration is zero at middle point ( equilibrium position )
maximum acceleration
= ω²A
= k / m x A
= 400 x .04
= 16 m / s
d )
At halfway point velocity will be √ 3 / 2 times the maximum velocity
velocity at mid point
= √ 3 / 2 x max velocity
.866 x
= .866 x 0.8
= .693 m /s