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Viefleur [7K]
1 year ago
12

according to newton's law of inertia, a railroad train in motion should continue going forever even if its engine is turned off.

we never observe this because railroad trains group of answer choices must go up and down hills. always have forces that oppose their motion. move too slowly. are much too heavy.
Physics
1 answer:
Umnica [9.8K]1 year ago
8 0

Unless acted upon by an external force, an object in motion tends to stay in motion, and an object at rest prefers to stay at rest.

We can also see that we regress when a car abruptly begins to move from a condition of rest. The inertia of repose also contributes to this. Our bodies have a tendency to stay in a condition of rest, but as soon as the automobile starts moving, we start to regress.

Unless influenced by an imbalanced force, an item at rest stays at rest, and an object in motion keeps moving in a straight path at a constant pace. Second Law of Motion by Newton.

Learn more about motion here-

brainly.com/question/22810476

#SPJ4

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Answer:

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3 years ago
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Define the following:
belka [17]
Define the following:
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Mechanical energy:
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a bullet with a mass of 4.0g and a speed of 650m/s is fired at a block of wood with a mass of 0.095kg. the block rests on a fric
n200080 [17]

Part a)

Here in this we can use momentum conservation as there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} +m_2v_{2f}

here we know that

m_1 = 0.004 kg

v_{1i} = 650 m/s

m_2 = 0.095

v_{2i} = 0

v_{2f} = 23 m/s

now by above equation

0.004*650 + 0.095* 0 = 0.004*v + 0.095*23

2.6 + 0 = 0.004*v + 2.185

v = 103.75 m/s

Part b)

Final kinetic energy of the system

KE_f = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2

KE_f = \frac{1}{2}*0.004*(103.75^2) + \frac{1}{2}*(0.095)*23^2

KE_f = 46.65 J

Initial Kinetic energy of the system will be

KE_f = \frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2

KE_f = \frac{1}{2}*0.004*(650^2) + \frac{1}{2}*(0.095)*0^2

KE_f = 845 J

So here kinetic energy is decreased for this system

final energy is less than initial energy

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i think its a, good luck on your test

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What area ?

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