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4 years ago

What is the advantage of using fluorescent bulbs over incandescent bulbs?

1 answer:

5 0

Incandescent bulbs work by conducting an electric current along a filament made of a long, thin piece of tungsten metal. The filament must be heated to temperatures of about 2,300 degrees Celsius to glow and emit a white-hot light. But the process transforms only 5 percent to 10 percent of the electricity used into visible light. The rest is transformed into heat, which can eventually increase the temperature of a room.

CFL bulbs, on the other hand, are made of glass tubes filled with gas and a small amount of mercury. The amount is so small that an old-fashioned glass thermometer holds 100 times as much mercury as one CFL bulb. Light is emitted when mercury molecules in a CLF bulb become excited by electricity running between two electrodes at its base. The mercury emits an invisible ultraviolet light that becomes visible when it hits the white coating inside the CFL bulb.

Basically, based on how they both work, fluorescent bulbs last longer and do not release as much heat as incandescent bulbs which means it's also better for the environment.

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A 6.2 kg ladder, 1.97 m long, rests on two sawhorses. Sawhorse A is 0.64 m from one end of the ladder, and sawhorse B is 0.17 m

Keith_Richards [23]

Answer:

42.69 N and 18.07 N

Explanation:

We are given that

Mass of ladder=6.2 kg

Length of ladder=1.97 m

Distance of Sawhorse A from one end=0.64 m

Distance of sawhorse B from other end=0.17 m

Let center of Ladder= $\frac{1.97}{2}=0.985 m$

Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m

Distance of sawhorse B from center of ladder=0.985-0.17=0.815 m

Force one ladder due to gravity=mg= $6.2\times 9.8=60.76N$

Where $g=9.8 m/s^2$

Torque applied on Sawhorse A= $0.345F_a$

Torque applied on Sawhorse B= $0.815F_b$

In equilibrium

$0.345F_a=0.815F_b$

$F_b=\frac{0.345}{0.815}F_a$

Total force= $F_a+F_b$

$F_a+\frac{0.345}{0.815}F_a=60.76$

$\frac{0.815F_a+0.345F_a}{0.815}=60.76$

$\frac{1.16}{0.815}F_a=60.76$

$F_a=\frac{60.76\times 0.815}{1.16}=42.69 N$

$F_b=\frac{0.345}{0.815}\times 42.69=18.07 N$

8 0

4 years ago

How many units measure one wavelength? a 16 b 8 c 2 d 4

pochemuha

B it makes more sense

8 0

4 years ago

Calculate the intensity of the sound waves from an electric guitar’s amplifier at a

Step2247 [10]

Answer:

a. 0.8 mW/m² b. 1.6 mW/m² c. 6.4 mW/m²

Explanation:

Intensity,I = P/A were P = power and A = area = 4πr² were r = distance from electric guitar = 5.0 m.

a. When P = 0.25 W, I = 0.25 W/4π5² = 0.25 W/100π = 0.00079 W/m² ≅ 0.0008 W/m² = 0.8 mW/m²

b. When P = 0.50 W, I = 0.50 W/4π5² = 0.50 W/100π = 0.00156 W/m² ≅ 0.0016 W/m² = 1.6 mW/m²

c. When P = 2.0 W, I = 2.0 W/4π5² = 2.0 W/100π = 0.00636 W/m² ≅ 0.0064 W/m² = 6.4 mW/m²

8 0

3 years ago

In this lab you will use a cart and a track to explore Newton's second law of motion. You will vary two different variables and

Savatey [412]

Answer:

Newtons II law:

It is defined as "the net force acting on the object is a product of mass and acceleration of the body" . Also it defines that the "acceleration of an object is dependent on net force and mass of the body".

Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.

Whenever the hanging weight moves downwards, the cart will accelerate to right side.

For the hanging weight/mass

When hanging weight of mass is m₁ and accelerate due to gravitational force g.

Therefore we can write F = m₁ .g

and the tension acts in upward direction T (negetive)

Now, Fnet = m₁ .g - T

= m₁.a

So From Newtons II law F = m.a

3 0

3 years ago

Read 2 more answers

What distance will an object cover in 20 seconds if it is moving at 8 m/s

Nitella [24]

Answer:

160 m

Explanation:

distance covered in 1 s = 8 m

therefore, distance covered in 20 s = 8 * 20 m = 160 m

4 0

3 years ago