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konstantin123 [22]
4 years ago
10

You decide to travel by car for your holiday visits this year. You leave early in the morning to avoid congestion on the roads.

This enables you to drive at a comfortable speed of 67.4 mph for 1.70 hours. However, after this time, you unexpectadly come to a stop for 23.4 min. Traffic starts moving again and you finish your travel at 54.0 mph for an additional 1.25 hours. How far did you travel on this trip? What was your average speed? There are 1609 meters in one mile.
Physics
1 answer:
podryga [215]4 years ago
5 0

Answer:

a) d = 182.08 miles

b) \overline{v} = 54.5 mph      

Explanation:

a) The distance can be found as follows:

d_{T} = d_{1} + d_{2} + d_{3}

d_{T} = v_{1}*t_{1} + v_{2}*t_{2} + v_{3}*t_{3}

d_{T} = 67.4 mph*1.70 h + 0*23.4 min + 54.0 mph*1.25 h = 182.08 miles = 292.9 km

b) The average speed can be calculated using the following equation:

\overline{v} = \frac{d_{f} - d_{i}}{t_{f} - t_{i}}

Where "f" is for final and "i" for initial

\overline{v} = \frac{182.08 miles - 0 miles}{(1.70 h + 23.4 min*\frac{1 h}{60 min} + 1.25 h) - 0 h} = 54.5 mph                

I hope it helps you!

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