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Westkost [7]
2 years ago
15

If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor

of 17?
Mathematics
1 answer:
choli [55]2 years ago
5 0
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
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One number is 3 times another. If the sum of the two numbers is 15, find the two numbers.
gregori [183]

Answer:

15/4 and 45/4

Step-by-step explanation:

Let x and y be the numbers

x = 3y

x+ y = 15

Substitute the first equation in to the second equation

3y+y = 15

4y = 15

y = 15/4

x = 3(15/4)

x = 45/4

The two numbers are 15/4 and 45/4

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Solve by the substitution method.
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Answer:

The unique solution to the system is (x,y){(-9,-3)}

Step-by-step explanation:

x - y = -6     equation 1

5x + 6y = -63     equation 2

We will find the value of x from equation 1.

x= y-6

Now put the value of x in equation 2.

5(y-6)+6y = -63

5y-30+6y = -63

Combine the like terms:

5y+6y= -63+30

11y = -33

Divide both sides by 11.

11y/11 = -33/11

y = -3

Now put the value y = -3 in x=y-6

x = y-6

x= -3-6

x= -9

Therefore The unique solution to the system is (x,y){(-9,-3)} ....

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Olivia bowled 5 games. Her scores were 80, 95, 100, 85, and 95. What is the mean of her scores for the 5 games? * A. 20 B. 72 C.
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Answer:

Step-by-step explanation:

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2. To implement the independent variable, the experimenter needs to divide the 100 volunteers into separate groups based on standardized tests of ability and achievements. He must also make sure that each groups’ students’ ability levels are the same. Then they would be given tasks as per their ability level.

3.The dependent variable here would be the academic achievements of the groups formed based on ability.

4. First, the volunteers’ achievement would be tested. Then based on their abilities as per standardized tests, they would be divided into groups of students with similar abilities. Then they would be given tasks as pr their abilities. Finally, their achievements would be measured to see if there is any significant difference in achievement between them before and after the grouping as per ability.

5.

6. Null Hypothesis: There would be no significant difference between the academic achievements in high school students of varying abilities due to separation into distinct groups based on standardized tests of ability and achievement.

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