The distance covered is 66 m and the velocity would be 17 m/s
<h3>What are the three equations of motion?</h3>
There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
As given in the problem, An antelope moving with a constant acceleration of 2m/s2 covers crosses a point where its velocity is 5m/s
distance =? meters
initial velocity(u) = 5 m/s
acceleration(a) = 2 m/s²
By using the second equation of motion given by newton
S = ut + 1/2at²
u= 5 m/s , a= 2 m/s² and t =6 seconds
S = 5*6 +0.5*2*6²
=66 m
to calculate the velocity after 6 seconds by using the first question of the motion
v = u + at
v = 5 + 2*6
v = 17 m/s
Thus, the distance covered is 66 m and the velocity would be 17 m/s
Learn more about equations of motion from here
brainly.com/question/5955789
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