Question

An antelope moving with constant acceleration of 2m/s2 covers crosses a point where its velocity is 5m/s. After 6s how much distance it has covered and what is its velocity?

Answer 1

The distance covered is 66 m and the velocity would be 17 m/s

What are the three equations of motion?

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

As given in the problem, An antelope moving with a constant acceleration of 2m/s2 covers crosses a point where its velocity is 5m/s

distance  =? meters

initial velocity(u) = 5  m/s

acceleration(a) = 2 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

u= 5  m/s , a= 2 m/s² and t =6 seconds

S = 5*6 +0.5*2*6²

  =66 m

to calculate the velocity after 6 seconds by using the first question of the motion

v = u + at

v = 5 + 2*6

v = 17 m/s

Thus, the distance covered is 66 m and the velocity would be 17 m/s

Learn more about equations of motion from here

brainly.com/question/5955789

#SPJ1