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MrRissso [65]
3 years ago
11

A cat weighs 8.5 pounds on Earth. how much would this cat weigh on Neptune?

Physics
1 answer:
Oduvanchick [21]3 years ago
3 0
Hello there!

The answer is 10.115 pounds.
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4 years ago
Left arm has area 10.0 cm2, right has area 5.00 cm2. 100 g of water isadded to right side. a) Determine the length of the water
Masja [62]

Answer:

0.49  cm

Explanation:

We are given that

A_1=10 cm^2

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Mass of water,m=100 g

a.\rho_w=1 g/cm^3

Volume,V=\frac{mass}{density}=\frac{100}{1}=100 cm^3

Length of water column in the right arm=L=\frac{V}{A_2}=\frac{100}{5}=20 cm

b.\rho_m=13.6 g/cm^3

In equilibrium condition  

Pressure at point A=Pressure at point B

P+\rho_mg(h+h_2)=P+\rho_wgL

hA_1=h_2A_2

h_2=\frac{hA_1}{A_2}

13.6\times 9.8(h+h(\frac{A_1}{A_2}))=1\times 9.8\times 20

13.6\times h(\frac{A_2+A_1}{A_2})=20

h=\frac{20A_2}{13.6(A_2+A_1)}

h=\frac{20\times 5}{13.6\times (10+5)}=0.49 cm

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