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nlexa [21]
3 years ago
11

9. If the frequency of a certain light is 3.8 x 1024 Hz, what is the energy of this light?

Physics
1 answer:
german3 years ago
4 0

Answer:

E=hf

Were, h = Planck constant 6.67*10^11

E=3.8*10^24 * 6.67*10^11= 2.508*q0^36j

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WILL UPVOTE!!!Physics help please!!
liubo4ka [24]
Speed v = initial speed u + acceleration a x time t 
v=u+at = 2 + 4*3 = 14 m/s

8 0
3 years ago
[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeti
zalisa [80]

Option B i.e discretion is the right and correct answer.

[C]utting programs that were not effective or essential and even some that were, but are now unaffordable; and precisely targeting our investments. Every department will feel the impact of these reductions as they cut programs or tighten their belts to free up more resources for areas critical to economic growth. —President Barack Obama, 2012 Budget Message of the President.

The President above clearly refers to the Discretion Spending where portion of the budget is decided by Congress through the annual appropriations.

3 0
3 years ago
Read 2 more answers
Explain the causes of atmospheric pressure and why it changes with altitude?​
Verdich [7]

Answer:

As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude

4 0
2 years ago
. What is the velocity of a free-<br> falling object after 5 seconds?<br> (Use 10 m/s2 for gravity.)
Viefleur [7K]

Answer:

vf = 50 m/s

Explanation:

The equation for this kinematic problem is:

vf = vi + at

We are given:

a = 10m/s^2

vi = 0m/s

t = 5 sec

vf = ?

Solve for final velocity:

vf = 0 + 10(5)

vf = 50 m/s

8 0
3 years ago
A 2 kg ball of clay moving at 35 m/s strikes a 10 kg box initially at rest. What is the velocity of the box after the collision?
Ainat [17]

Answer:

V = 5.83 m/s

Explanation:

Given that,

Mass of a ball of a clay, m = 2 kg

Initial speed of the clay, u = 35 m/s

Mass of a box, m' = 10 kg

Initially, the box was at rest, u' = 0

We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.

mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{2\times 35+10\times 0}{2+10}\\\\V=5.83\ m/s

So, the velocity of the box after the collision is equal to 5.83 m/s.

4 0
3 years ago
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