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AlladinOne [14]
3 years ago
7

(b) Calculate the momentum when a mass of 40kg is moving with a velocity of 20m/s in the forward

Physics
2 answers:
mamaluj [8]3 years ago
8 0

Answer:

800kgm/s

Explanation:

momentum= mass×velocity

= 40×20

= 800kgm/s

Alenkasestr [34]3 years ago
6 0

Explanation:

momentum = mass x velocity

momentum = 40 x 20 = 800kgm/s

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An object moving in a constant velocity will always have a
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Answer:

constant velocity unless acted on my an opposite force

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Explain how to find the acceleration of an object that has one-dimensional horizontal motion.
Nostrana [21]
Acceleration is how much the velocity changes within a period of time so,

Acceleration= is the change in velocity divided by change in time

your units will be m/s squared
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2 years ago
Which of the following decreases with increasing atomic number in Group 2A?
Semenov [28]
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7 0
3 years ago
Read 2 more answers
Find the difference between two masses measured as 123.6 grams and 115.972 grams. Express the answer to the correct number of si
xxTIMURxx [149]

Answer:

The difference is 7.6 grams.

Explanation:

In mathematics the difference of two numbers is express as the subtraction between them:

         

a-b

So to find out the difference between the two measured masses, a will be represented by 123.6 grams since is the bigger number, and b by 115.972 grams.

Therefore, it is get:

123.6grams-115.972grams = 7.6grams

<u>Hence, the difference is 7.6 grams. </u>

The result of 7.628 will be expressed as 7.6 to have the correct number of significant figures.          

 

Notice how that can be express in units of kilograms too since there is 1000 gram in 1 kilogram:

7.6grams . \frac{1Kg}{1000grams} ⇒ 7.6x10^{-3}Kg

8 0
3 years ago
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / P_{y}

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

7 0
3 years ago
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