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1 year ago

Please help, will give brainliest! Please reference the photo attached

Mathematics

1 answer:

Vlad [161]1 year ago

5 0

Answer:

Step-by-step explanation:

哇，我喜歡吃很多食物，因為我喜歡並喜歡它。

Wa, wǒ xǐhuān chī hěnduō shíwù, yīnwèi wǒ xǐhuān bìng xǐhuān tā.

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The heights (in inches) of the starting players on a high school basketball team are as follows: 72, 75, 78, 72, 73.

MakcuM [25]

Answer:

There are 5 starting players.

The mean is 74

The median is 73

Step-by-step explanation:

6 0

3 years ago

How many 1-ft square tiles would it take to cover the floor of a square room that is 13 ft on each side?

Anni [7]

It would take 169 tiles(13x13=169)

8 0

3 years ago

Read 2 more answers

I need help with 11 and 12

Yakvenalex [24]

Answer:

Both are inverse pairs

Step-by-step explanation:

Question 11

$g(x)= 4 + \dfrac{8}{5}x$

(a) Rename g(x) as y

$y = 4 + \dfrac{8}{5}x$

(b) Solve for x :

$\dfrac{8}{5}x = y - 4$

(c) Multiply each side by ⅝

$x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}$

(d) Switch x and y

$y = \dfrac{5}{8}x - \dfrac{5}{2}$

(e) Rename y as the inverse function

$g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}$

(f) Compare with your function

$f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)$

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

Question 12

h(x)= x - 2

(a) Rename h(x) as y

y = x - 2

(b) Solve for x:

x = y + 2

(c) Switch x and y

y = x + 2

(e) Rename y as the inverse function

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

5 0

3 years ago

You have 80 pieces of fabric to make a wall hanging. Each piece of fabric is a square with a side length of 5 inches. You use as

tensa zangetsu [6.8K]

Okay. fist off don't think of them as 5 units each, but 1. so if you were to put it on graphing paper and box squares each time. you would be able to get 8 in for both sides to make a square. Area then would be 1600ft squared because 8 ×5 is 40 and 40×40 is 1600. then you calculate how many squares you used. 8×8=64. and 80-64=16 so 16 pieces are left over. then 9×9 (increasing the square) is 81. so 17 pieces to increase it.

5 0

3 years ago

Read 2 more answers

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

4 years ago

Read 2 more answers