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Alla [95]
3 years ago
11

Determine the rate of change of the following linear equation as it translates from (-5, -1) to any other point on the line.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0
The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).
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8. Find the value of x so that line mis parallel to line l. (1 p<br><br> (3x+21)°<br><br> (4x-7)
dybincka [34]

Answer: The value of x is 28.

Step-by-step explanation:

Since line m is parallel to line l.

So, we assume that

(3x+21)° and (4x-7)° are corresponding angles.

And we know that , corresponding angles formed when a transversal cut the  parallel line are equal.

So, they must be equal to each other.

3x+21=4x-7\\\\21+7=4x-3x\\\\28^\circ=x

Hence, the value of x is 28.

6 0
3 years ago
The diameters of a circle is 7m. Find its area to the nearest tenth?? Help please
Lady bird [3.3K]

Area =\pi r^{2}

The diameter is double the length of the radius

7 ÷ 2 = 3.5

3.5 × 3.5 = 12.25

12.25\pi = 38.4845100064751

38.4845100064751 rounded to the nearest tenth is 38.5

8 0
2 years ago
Read 2 more answers
How does the graph of g(x) = -(x + 3)4 compare to the parent function of f(x) = xº?
AnnyKZ [126]

Answer:

g(x) is shifted 3 units to the left and reflected over the x-axis.

Step-by-step explanation:

8 0
3 years ago
The height of the sail on a boat is 7 feet less than 3 times the length of its base. If the
xxTIMURxx [149]

Answer:

Base=8 feet

Height=17 feet

Step-by-step explanation:

Let

Base=x

Height=3x-7

Area=68 square feet

Area of the sail boat=1/2 * base * height

68 = 1/2 * x * (3x-7)

Cross product

68 * 2 =(1) * (x) * (3x-7)

136 = 3x^2 - 7x

3x^2 - 7x - 136=0

Using quadratic formula

x= -b +or- √b^2 - 4ac / 2a

= -(-7) +or- √(-7)^2 - (4)(3)(-136) / 2(3)

= 7 +or- √49 - (-1632) / 6

= 7 +or- √49+1632) / 6

= 7 +or- √1681 / 6

=7 +or- 41 /6

x= 7+41 / 6 or 7-41 / 6

=48/6 or -34/6

=8 or -17/3

Answer:

Step-by-step explanation:

Let

Base=x

Height=3x-7

Area=68 square feet

Area of the sail boat=1/2 * base * height

68 = 1/2 * x * (3x-7)

Cross product

68 * 2 =(1) * (x) * (3x-7)

136 = 3x^2 - 7x

3x^2 - 7x - 136=0

Base of the boat can't be a negative value

Therefore,

Base = x = 8 feet

Height= 3x-7

=3(8)-7

=24-7

=17 feet

3 0
3 years ago
Plz help me well mark brainliest if you are correct!.....
Alex17521 [72]

Answer:

The first one is the answer to the question

4 0
3 years ago
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