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Vladimir79 [104]
3 years ago
6

A single die is rolled twice. Find the probability of rolling a 3 the first time and a 2 the second time

Mathematics
2 answers:
mart [117]3 years ago
8 0
I would love to help but what’s the question to this problem
Lubov Fominskaja [6]3 years ago
7 0

Answer:

1/36

Step-by-step explanation:

A single roll of a die has six possible outcomes and each consecutive roll is independent of all previous rolls. The probability of each possible outcome is 1/6.

P (3 and 2)= P(3)*P(2)= 1/6 *1/6=1/36

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Read 2 more answers
A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
castortr0y [4]

Answer:

The answer is option 2.

Step-by-step explanation:

In the question, the independent variable is time and dependent is distance. As the time changes, the distance will also change it means the distance depends on time.

For example,

d = 0.5 + 5t

Let t = 1,

d = 0.5 + 5(1)

d = 5.5 \: miles

Let t = 5,

d = 0.5 + 5(5)

d = 25.5 \: miles

Therfore, as time increases, distance will also increase.

4 0
3 years ago
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