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3 years ago

A single die is rolled twice. Find the probability of rolling a 3 the first time and a 2 the second time

Mathematics

2 answers:

mart [117]3 years ago

8 0

I would love to help but what’s the question to this problem

Lubov Fominskaja [6]3 years ago

7 0

Answer:

1/36

Step-by-step explanation:

A single roll of a die has six possible outcomes and each consecutive roll is independent of all previous rolls. The probability of each possible outcome is 1/6.

P (3 and 2)= P(3)*P(2)= 1/6 *1/6=1/36

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VikaD [51]

Answer:

This time all of them are right

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Step-by-step explanation:

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vitfil [10]

Answer:

Step-by-step explanation:

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MrRissso [65]

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3 years ago

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NNADVOKAT [17]

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2 years ago

There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model

Helga [31]

$\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill$

$A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}$

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1 year ago