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den301095 [7]
2 years ago
11

How do the bonding and antibonding MOs formed from a given pair of AOs compare to each other with respect to:

Chemistry
1 answer:
schepotkina [342]2 years ago
8 0

The node is the region of an orbital where the probability of finding the electron is zero, so the nodal plane is the plane that bisects the node perpendicular to the bond axis.

<h3>What is atomic orbital?</h3>

An atomic orbital is a function in atomic theory and quantum mechanics that describes the location and wave-like behavior of an electron in an atom. This formula can be used to calculate the likelihood of locating any atom's electron in any given location surrounding the nucleus. The phrase atomic orbital can also refer to the actual region or place where the electron is projected to be present given the orbital's mathematical form.

Each orbital in an atom is defined by a set of values of the three quantum numbers n, l, and ml, which correspond to the energy, angular momentum, and an angular momentum vector component of the electron, respectively (magnetic quantum number).

To learn more about atomic orbital visit:

brainly.com/question/28240666

#SPJ4

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what element is found in group 6 and period 4? Based on its location, is the element more similar to tungsten or to iron?
GarryVolchara [31]

the asnwer is berlinuim  become a power geek like me  plz itl help u

6 0
3 years ago
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
3 years ago
Laughing gas (nitrous oxide, N20) is some-
alukav5142 [94]

Answer: 109.2g

Explanation:

1 mole N2O = 34 g

46.4g = 46.4/34 moles = 1.365 moles

1 mole N2O is from 1 mole NH4NO3

1.365 moles NH4NO3 = 1.365*80g = 109.2g

6 0
3 years ago
What mass of hydrochloric acid (in grams) can 2.7 g of sodium bicarbonate neutralize? (Hint: Begin by writing a balanced equatio
Julli [10]

Answer:

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

Explanation:

Step 1: Data given

Mass of sodium bicarbonate = 2.7 grams

Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

Step 3: Calculate moles NaHCO3

moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

Step 4: Calculate moles HCl

For 1 mol NaHCO3 we need 1 mol HCl

For 0.032 moles NaHCO3 = 0.032 moles HCl

Step 5: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

3 0
4 years ago
What is the precipitate for CuSO4+NaOH<br> (Balancing Equations)
jeka57 [31]

Answer:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

Explanation:

5 0
4 years ago
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