Answer:
mass of platinum = 2526.12 g
Explanation:
Given data:
Mass of water = 125 g
Initial temperature of water= 100.0°C
Initial temperature of Pt = 20.0°C
Final temperature = 235°C
Specific heat of Pt = 0.13 j/g°C
Specific heat of water = 4.184 j/g°C
Mass of platinum = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Q(w) = Q(Pt)
m.c. (T2 - T1) = m.c.
(T2 - T1)
125 g × 4.184 j/g°C × (235°C - 100.0°C) = m × 0.13 j/g°C × (235°C - 20°C)
125 g × 4.184 j/g°C × 135°C = m × 0.13 j/g°C × 215°C
70605 j = m×27.95 j/g
m = 70605 j /27.95 j/g
m = 2526.12 g
Answer:
I think your correct but I'm not so sure
Answer:
H3PO4 + 3NaOH ----> Na3PO4 + 3H2O
Explanation:
The balanced equation is given below
H3PO4 + 3NaOH ----> Na3PO4 + 3H2O
7 is the pancreas and 8 is i can’t see the other choices but for diabetes the glucose levels will be a lot higher
Answer:
The answer is C. the energy transferred between objects at different temperatures.
Explanation:
I did some research, I hope this helps.
