What is the precipitate for CuSO4+NaOH<br> (Balancing Equations)

During osmosis, water moves from a region of _____ to a region of _____.both "high solvent concentration; low solvent concentrat

Vinil7 [7]

Answer: -

Osmosis is the process by which water molecules move from a region of high solvent concentration to low solvent concentration.

Now in any solution there are just solute and solvent.

If the amount of solvent is more in a solution then the amount of solute would be less.

Again if the amount of solvent is less in a solution then amount of solute is more.

Thus we can write that :- osmosis is the movement of water molecules from a region of low solute concentration to high solute concentration.

5 0

4 years ago

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Please Hurry this is already overdue

Troyanec [42]

Answer:

According to the chart, the period and string length are not the same. Regardless of string length. The chart says that "period = seconds 10"

Explanation:

So for example in Trial 1. The period equaled 8.7, so in turn you would times 8.7 by 10 and get 87. Which is not equal to the string length. For they are also measured in two different measurements.

7 0

3 years ago

The following properties are either physical or chemical. Which one is different from the rest based on those two category? A.)

Oduvanchick [21]

Answer:

A.)physical B.)physical C.)physical D.)chemical

5 0

3 years ago

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Write ionic equations for any three of the following:

worty [1.4K]

1.

The ionic equation is:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H2O(l)

The required dissociations are

HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)

NaOH(aq) → Na⁺(aq) + OH⁻(aq)

NaNO₃(aq) → Na⁺(aq) + NO₃⁻(aq)

So, the ionic equation is

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

2.

The ionic equation is

H⁺(aq) + Cl⁻(aq) + K⁺(aq) + OH⁻(aq) → K⁺(aq) + Cl⁻(aq) + H₂O(l)

HCl(aq) + KOH(aq) → KCl(aq) + H2O(l)

The required dissociations are

HCl(aq) → H⁺(aq) + Cl⁻(aq)

KOH(aq) → K⁺(aq) + OH⁻(aq)

KCl(aq) → K⁺(aq) + Cl⁻(aq)

So, the ionic equation is

H⁺(aq) + Cl⁻(aq) + K⁺(aq) + OH⁻(aq) → K⁺(aq) + Cl⁻(aq) + H₂O(l)

3.

The ionic equation is

2H⁺(aq) + SO₄²⁻(aq) + Mg²⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

+ 2H₂O(l)

H₂SO₄(aq) + Mg(OH)₂(aq) → MgSO₄(aq) + 2H2O(l)

The required dissociations are

H₂SO₄(aq) → 2H⁺(aq) + SO₄²⁻(aq)

Mg(OH)₂(aq) → Mg²⁺(aq) + 2OH⁻(aq)

MgSO₄(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

So, the ionic equation is

2H⁺(aq) + SO₄²⁻(aq) + Mg²⁺(aq) + 2OH⁻(aq) → Mg²⁺(aq) + SO₄²⁻(aq)

+ 2H₂O(l)

Learn more about ionic equations here:

brainly.com/question/11628165

5 0

3 years ago

Draw the structure of 2 methyl,but-3-ene

Maslowich

Answer:

Please find the structure attached as an image

Explanation:

Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.

- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.

- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).

N.B: In the structure attached below, the counting is from the left to right (→).

5 0

2 years ago

What is the precipitate for CuSO4+NaOH (Balancing Equations)