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Sergio [31]
3 years ago
9

Complete the equation to show how hydrofluoric acid, HF, acts as a Brønsted-Lowry acid in water. Balanced equation:

Chemistry
1 answer:
shepuryov [24]3 years ago
8 0

Answer : The balanced equation is,

HF+H_2O\rightleftharpoons H_3O^++F^-

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

The balanced chemical reaction will be,

HF+H_2O\rightleftharpoons H_3O^++F^-

In this reaction, hydrofluoric acid is act as a Bronsted Lowry-acid because it donate one hydrogen ion to H_2O and H_3O^+ is act as a Bronsted Lowry-base because it accept one hydrogen ion from HF.

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Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (Q), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (\bar {Q}), en kilojoules por mol, dividido por su masa molar (M), en gramos por mol:

Q = \frac{\bar Q}{M} (1)

A continuación, analizamos cada caso:

Metano

Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }

Q = 50.125\,\frac{kJ}{g}

1 gramo de metano aporta 50.125 kilojoules.

Octano

Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }

Q = 48.246\,\frac{kJ}{mol}

1 gramo de metano aporta 48.246 kilojoules.

3 0
2 years ago
A 5.00 gram sample of water is heated so that its temperature increases from 10.0°C to 15.0°C. What is the
tresset_1 [31]

Answer:

15.0°C

Explanation:

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3 0
3 years ago
The shape of the nucleus is maintained by
dexar [7]
B. the necular lamina
8 0
3 years ago
How many milliliters of manganese metal, with a density of 7.43 g/mL, would be needed to produce 21.7 grams of hydrogen gas in t
Alla [95]
First compute the number of grams of manganese metal required to make 21.7 grams of H2. 
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams 
Now density = mass/volume 
7.43 = 596.75/volume 
volume = 596.75/7.43 = 80.31 mL 
80.31 mL is the amount of manganese needed.
3 0
3 years ago
Is this the right answer to this question....?
givi [52]

Transport of Na+ from a place of low concentration to a place of higher concentration. <u>This is the right answer.</u>

<u />

The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.

One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.

Learn more about Active transport here:-brainly.com/question/25802833

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3 0
1 year ago
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